I do write the following SQL query in LINQ c#
SELECT max(creation_date) from TRS where approval_status='APPROVED' and transaction_type in ('Sale','PRE')
I tried building below query on a list as follows
var session = txns.Where(a => a.transaction_type.Equals("SALE"))
.Where(a => a.transaction_type.Equals("PRE"))
.Where(a => a.approval_status.Equals("APPROVED"))
.OrderByDescending(a => a.creation_date).Select(a => a.creation_date).FirstOrDefault();
The above query didnt work as I wasn't sure of how to use Max and OR condition in LINQ c#
May I know a better solution?
In LINQ, we can use Where() clause in the query to define multiple conditions, as shown below. This is how we can use LINQ where clause filtering operator to filter data based on conditions.
In a LINQ query, the first step is to specify the data source. In C# as in most programming languages a variable must be declared before it can be used. In a LINQ query, the from clause comes first in order to introduce the data source ( customers ) and the range variable ( cust ).
Linq Namespace. Provides classes and interfaces that support queries that use Language-Integrated Query (LINQ).
var session = txns
.Where(a => a.transaction_type.Equals("SALE") || a.transaction_type.Equals("PRE"))
.Where(a => a.approval_status.Equals("APPROVED"))
.Select(a=>a.creation_date).Max();
or
var txtypes=new[]{"SALE","PRE"};
var session = txns
.Where(a => txtypes.Contains(a.transaction_type))
.Where(a => a.approval_status.Equals("APPROVED"))
.Select(a=>a.creation_date).Max();
or
var session = txns
.Where(a => a.transaction_type.Equals("SALE") || a.transaction_type.Equals("PRE"))
.Where(a => a.approval_status.Equals("APPROVED"))
.Max(a=>a.creation_date);
You can use ||
operator to combine your two conditions or you can use Contains
which would generate a query like SELECT IN (....)
var transcationTypes = new[] {"SALE", "PRE"};
var sessions = txns.Where(a => transcationTypes.Contains(a.transaction_type)
&& a.approval_status == "APPROVED")
.Select(a => a.creation_date)
.Max();
Once you have filtered out the results you can use Max
to select the maximum value.
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