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How do I implement TypeAdapterFactory in Gson?

How do I implement type TypeAdapterFactory in Gson?

The main method of create is generic. Why?

The registration method registerTypeAdapterFactory() does not receive type a type argument. So, how does Gson know which classes are processed by the factory?

Should I implement one factory for multiple classes, or can I implement one for many classes?

If I implement one factory for multiple classes, then what should I return in case of out-of-domain type argument?

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Suzan Cioc Avatar asked Mar 10 '14 17:03

Suzan Cioc


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1 Answers

When you register a regular type adapter (GsonBuilder.registerTypeAdapter), it only generates a type adapter for THAT specific class. For example:

public abstract class Animal { abstract void speak(); } public class Dog extends Animal {    private final String speech = "woof";    public void speak() {        System.out.println(speech);    } }  // in some gson related method gsonBuilder.registerTypeAdapter(Animal.class, myTypeAdapterObject); Gson g = gsonBuilder.create(); Dog dog = new Dog(); System.out.println(g.toJson(dog)); 

If you did this, then Gson will not use your myTypeAdapterObject, it will use the default type adapter for Object.

So, how can you make a type adapter object that can convert ANY Animal subclass to Json? Create a TypeAdapterFactory! The factory can match using the generic type and the TypeToken class. You should return null if your TypeAdapterFactory doesn't know how to handle an object of that type.

The other thing TypeAdapterFactory can be used for is that you can't CHAIN adapters any other way. By default, Gson doesn't pass your Gson instance into the read or write methods of TypeAdapter. So if you have an object like:

public class MyOuterClass {     private MyInnerClass inner; } 

There is no way to write your TypeAdapter<MyOuterClass> that knows how to use your TypeAdapter<MyInnerClass> without using the TypeAdapterFactory. The TypeAdapterFactory.create method DOES pass the Gson instance, which allows you to teach your TypeAdapter<MyOuterClass> how to serialize the MyInnerClass field.


Generally, here is a good standard way to begin to write an implementation of a TypeAdapterFactory:

public enum FooAdapterFactory implements TypeAdapterFactory {     INSTANCE; // Josh Bloch's Enum singleton pattern      @SuppressWarnings("unchecked")     @Override     public <T> TypeAdapter<T> create(Gson gson, TypeToken<T> type) {         if (!Foo.class.isAssignableFrom(type.getRawType())) return null;          // Note: You have access to the `gson` object here; you can access other deserializers using gson.getAdapter and pass them into your constructor         return (TypeAdapter<T>) new FooAdapter();     }      private static class FooAdapter extends TypeAdapter<Foo> {         @Override         public void write(JsonWriter out, Foo value) {             // your code         }          @Override         public Foo read(JsonReader in) throws IOException {             // your code         }     } } 
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durron597 Avatar answered Oct 10 '22 02:10

durron597