How does one handle ties when ranking results in a mysql query? I've simplified the table names and columns in this example, but it should illustrate my problem:
SET @rank=0;
SELECT student_names.students,
@rank := @rank +1 AS rank,
scores.grades
FROM student_names
LEFT JOIN scores ON student_names.students = scores.students
ORDER BY scores.grades DESC
So imagine the the above query produces:
Students Rank Grades
=======================
Al 1 90
Amy 2 90
George 3 78
Bob 4 73
Mary 5 NULL
William 6 NULL
Even though Al and Amy have the same grade, one is ranked higher than the other. Amy got ripped-off. How can I make it so that Amy and Al have the same ranking, so that they both have a rank of 1. Also, William and Mary didn't take the test. They bagged class and were smoking in the boy's room. They should be tied for last place.
The correct ranking should be:
Students Rank Grades
========================
Al 1 90
Amy 1 90
George 2 78
Bob 3 73
Mary 4 NULL
William 4 NULL
If anyone has any advice, please let me know.
EDIT: This is MySQL 4.1+ supported
Use:
SELECT st.name,
sc.grades,
CASE
WHEN @grade = COALESCE(sc.grades, 0) THEN @rownum
ELSE @rownum := @rownum + 1
END AS rank,
@grade := COALESCE(sc.grades, 0)
FROM STUDENTS st
LEFT JOIN SCORES sc ON sc.student_id = st.id
JOIN (SELECT @rownum := 0, @grade := NULL) r
ORDER BY sc.grades DESC
You can use a cross join (in MySQL, an INNER JOIN without any criteria) to declare and use a variable without using a separate SET
statement.
You need the COALESCE to properly handle the NULLs.
Sounds like a middleware rule that would be better expressed in code that sat between the database and the client.
If that's not possible, I'd recommend a stored procedure in MySQL to run the query as you wrote it and then modify the results using a cursor and an array.
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