How do I get the local IP address in Go?

Question

I want to get the computer's IP address. I used the code below, but it returns 127.0.0.1.

I want to get the IP address, such as 10.32.10.111, instead of the loopback address.

name, err := os.Hostname() if err != nil {      fmt.Printf("Oops: %v\n", err)      return }  addrs, err := net.LookupHost(name) if err != nil {     fmt.Printf("Oops: %v\n", err)     return }  for _, a := range addrs {     fmt.Println(a) }   

Answer 1

Here is a better solution to retrieve the preferred outbound ip address when there are multiple ip interfaces exist on the machine.

import (     "log"     "net"     "strings" )  // Get preferred outbound ip of this machine func GetOutboundIP() net.IP {     conn, err := net.Dial("udp", "8.8.8.8:80")     if err != nil {         log.Fatal(err)     }     defer conn.Close()      localAddr := conn.LocalAddr().(*net.UDPAddr)      return localAddr.IP } 

Answer 2

You need to loop through all network interfaces

ifaces, err := net.Interfaces() // handle err for _, i := range ifaces {     addrs, err := i.Addrs()     // handle err     for _, addr := range addrs {         var ip net.IP         switch v := addr.(type) {         case *net.IPNet:                 ip = v.IP         case *net.IPAddr:                 ip = v.IP         }         // process IP address     } } 

Play (taken from util/helper.go)