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For loop of two variables in Go

Tags:

go

The following for loop in Go isn't allowed,

for i := 0, j := 1; i < 10; i++, j++ {...}

What's the correct equivalent of the for-loop of two variables below?

for (int i = 0, j = 1; i < 10; i ++ , j ++) {...} 
like image 707
sof Avatar asked Jun 28 '16 16:06

sof


2 Answers

You don't have a comma operator to join multiple statements, but you do have multiple assignment, so this works:

package main

import (
    "fmt"
)

func main() {
    for i, j := 0, 1; i < 10; i, j = i+1, j+1 {
        fmt.Println("Hello, playground")
    }
}
like image 124
twotwotwo Avatar answered Nov 20 '22 03:11

twotwotwo


Although above Answer is accepted, and it fully satisfy the need. But I would like to contribute some further explanation to it.

Golang Does not support many things which could be done in simple terms. For loop is a most common example of this. The beauty of Go's For loop is that it merges many modern style of looping into one keyword.

Similarly Golang do with Multiple Variable declaration and assignment. According to above mentioned problem, We could solve multi-variable for loop with this simple tool which Golang provides us. If you want to look into further explanation, this question provide further details and way of declaring multiple variables in one statement.

Coming back to for loop, If we want to declare variable of same datatype we can declare them with this

var a,b,c string

but we use short hand in for loop so we can do this for initializing them with same value

  i,j := 0,1

Different Datatypes and Different Values

and if we want to declare different type of variables and want to assign different values we can do this by separating variables names and after := different values by comma as well. for example

 c,i,f,b := 'c',23423,21.3,false

Usage of Assignment Operator

Later on, we can assign values to multiple variables with the same approach.

    x,y := 10.3, 2
    x,y = x+10, y+1

Mixing Struct and Normal types in single statement

Even we can use struct types or pointers the same way. Here is a function to iterate Linked list which is defined as a struct

func (this *MyLinkedList) Get(index int) int {
    for i,list := 0,this; list != nil; i,list = i+1,list.Next{
        if(i==index){
            return list.Val
        }
    }
    return -1
}

This list is defined as

type MyLinkedList struct {
      Val int
      Next *MyLinkedList

 }

Answering to Original Problem

Coming to the origin Question, Simply it could be done

for i, j := 0, 1; i < 10; i, j = i+1, j+1 {
        fmt.Println("i,j",i,j)
    }
like image 30
Abdul Rehman Avatar answered Nov 20 '22 02:11

Abdul Rehman