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How do I get the first n characters of a string without checking the size or going out of bounds?

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How do you get the first n characters of a string?

To access the first n characters of a string in Java, we can use the built-in substring() method by passing 0, n as an arguments to it. 0 is the first character index (that is start position), n is the number of characters we need to get from a string. Note: The extraction starts at index 0 and ends before index 3.

How do I retrieve the first 5 characters from a string?

string str = (yourStringVariable + " "). Substring(0,5). Trim();

How do I find the first 10 characters of a string?

How to find the first 10 characters of a string in C#? To get the first 10 characters, use the substring() method. string res = str. Substring(0, 10);


Here's a neat solution:

String upToNCharacters = s.substring(0, Math.min(s.length(), n));

Opinion: while this solution is "neat", I think it is actually less readable than a solution that uses if / else in the obvious way. If the reader hasn't seen this trick, he/she has to think harder to understand the code. IMO, the code's meaning is more obvious in the if / else version. For a cleaner / more readable solution, see @paxdiablo's answer.


Don't reinvent the wheel...:

org.apache.commons.lang.StringUtils.substring(String s, int start, int len)

Javadoc says:

StringUtils.substring(null, *, *)    = null
StringUtils.substring("", * ,  *)    = "";
StringUtils.substring("abc", 0, 2)   = "ab"
StringUtils.substring("abc", 2, 0)   = ""
StringUtils.substring("abc", 2, 4)   = "c"
StringUtils.substring("abc", 4, 6)   = ""
StringUtils.substring("abc", 2, 2)   = ""
StringUtils.substring("abc", -2, -1) = "b"
StringUtils.substring("abc", -4, 2)  = "ab"

Thus:

StringUtils.substring("abc", 0, 4) = "abc"

Apache Commons Lang has a StringUtils.left method for this.

String upToNCharacters = StringUtils.left(s, n);

String upToNCharacters = String.format("%."+ n +"s", str);

Awful if n is a variable (so you must construct the format string), but pretty clear if a constant:

String upToNCharacters = String.format("%.10s", str);

docs


There's a class of question on SO that sometimes make less than perfect sense, this one is perilously close :-)

Perhaps you could explain your aversion to using one of the two methods you ruled out.

If it's just because you don't want to pepper your code with if statements or exception catching code, one solution is to use a helper function that will take care of it for you, something like:

static String substring_safe (String s, int start, int len) { ... }

which will check lengths beforehand and act accordingly (either return smaller string or pad with spaces).

Then you don't have to worry about it in your code at all, just call:

String s2 = substring_safe (s, 10, 7);

instead of:

String s2 = s.substring (10,7);

This would work in the case that you seem to be worried about (based on your comments to other answers), not breaking the flow of the code when doing lots of string building stuff.