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How do I dynamically create functions that are accessible in a parent scope?

Here is an example:

function ChildF()
{
  #Creating new function dynamically
  $DynFEx =
@"
  function DynF()
  {
    "Hello DynF"
  }
"@
  Invoke-Expression $DynFEx
  #Calling in ChildF scope Works
  DynF 
}
ChildF
#Calling in parent scope doesn't. It doesn't exist here
DynF

I was wondering whether you could define DynF in such a way that it is "visible" outside of ChildF.

like image 865
tellingmachine Avatar asked Jul 14 '09 05:07

tellingmachine


4 Answers

Another option would be to use the Set-Item -Path function:global:ChildFunction -Value {...}

Using Set-Item, you can pass either a string or a script block to value for the function's definition.

like image 78
Steven Murawski Avatar answered Nov 18 '22 05:11

Steven Murawski


The other solutions are better answers to the specific question. That said, it's good to learn the most general way to create global variables:

# inner scope
Set-Variable -name DynFEx -value 'function DynF() {"Hello DynF"}' -scope global

# somewhere other scope
Invoke-Expression $dynfex
DynF

Read 'help about_Scopes' for tons more info.

like image 27
Richard Berg Avatar answered Nov 18 '22 06:11

Richard Berg


You can scope the function with the global keyword:

function global:DynF {...}
like image 9
Shay Levy Avatar answered Nov 18 '22 07:11

Shay Levy


A more correct and functional way to do this would be to return the function body as a script block and then recompose it.

function ChildF() {
    function DynF() {
        "Hello DynF"
    }
    return ${function:DynF}
}
$DynFEx = ChildF
Invoke-Expression -Command "function DynF { $DynFEx }"
DynF
like image 2
intrepidis Avatar answered Nov 18 '22 07:11

intrepidis