Here is an example:
function ChildF()
{
#Creating new function dynamically
$DynFEx =
@"
function DynF()
{
"Hello DynF"
}
"@
Invoke-Expression $DynFEx
#Calling in ChildF scope Works
DynF
}
ChildF
#Calling in parent scope doesn't. It doesn't exist here
DynF
I was wondering whether you could define DynF in such a way that it is "visible" outside of ChildF.
Another option would be to use the Set-Item -Path function:global:ChildFunction -Value {...}
Using Set-Item
, you can pass either a string or a script block to value for the function's definition.
The other solutions are better answers to the specific question. That said, it's good to learn the most general way to create global variables:
# inner scope
Set-Variable -name DynFEx -value 'function DynF() {"Hello DynF"}' -scope global
# somewhere other scope
Invoke-Expression $dynfex
DynF
Read 'help about_Scopes' for tons more info.
You can scope the function with the global
keyword:
function global:DynF {...}
A more correct and functional way to do this would be to return the function body as a script block and then recompose it.
function ChildF() {
function DynF() {
"Hello DynF"
}
return ${function:DynF}
}
$DynFEx = ChildF
Invoke-Expression -Command "function DynF { $DynFEx }"
DynF
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