Array of function pointers in C

Question

I'm having really hard time comprehending the syntax for function pointers. What I am trying to do is, have an array of function pointers, that takes no arguments, and returns a void pointer. Can anyone help with that?

Answer 1

1. First off, you should learn about cdecl:

   cdecl> declare a as array 10 of pointer to function(void) returning pointer to void
   void *(*a[10])(void )
   

2. You can do it by hand - just build it up from the inside:

   a

   is an array:

   a[10]

   of pointers:

   *a[10]

   to functions:

   (*a[10])

   taking no arguments:

   (*a[10])(void)

   returning void *:

   void *(*a[10])(void)

3. It's much better if you use typedef to make your life easier:

   typedef void *(*func)(void);
   

   And then make your array:

   func a[10];