In C# I can declare a list declaratively, in other words declare its structure and initialise it at the same time as follows:
var users = new List<User>
{
new User {Name = "tom", Age = 12},
new User {Name = "bill", Age = 23}
};
Ignoring the differences between a List in .Net and a List in Scala (ie, feel free to use a different collection type), is it possible to do something similar in Scala 2.8?
UPDATE
Adapting Thomas' code from below I believe this is the nearest equivalent to the C# code shown:
class User(var name: String = "", var age: Int = 0)
val users = List(
new User(name = "tom", age = 12),
new User(name = "bill", age = 23))
What about:
case class User(name: String, age: Int)
val users = List(User("tom", 12), User("bill", 23))
which will give you:
users: List[User] = List(User(tom,12), User(bill,23))
val users = User("tom", 12) :: User("bill", 23) :: Nil
You could also use Scalas tupel class:
val users = ("tom", 12) :: ("bill", 23) :: Nil
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