How do I create an image in PIL using a list of RGB tuples?

Question

Suppose I have a list of pixels (represented as tuples with 3 RGB values) in a list that looks like list(im.getdata()), like this:

[(0,0,0),(255,255,255),(38,29,58)...] 

How do I create a new image using RGB values (each tuple corresponds to a pixel) in this format?

Thanks for your help.

Answer 1

You can do it like this:

list_of_pixels = list(im.getdata()) # Do something to the pixels... im2 = Image.new(im.mode, im.size) im2.putdata(list_of_pixels) 

Answer 2

You can also use scipy for that:

#!/usr/bin/env python  import scipy.misc import numpy as np  # Image size width = 640 height = 480 channels = 3  # Create an empty image img = np.zeros((height, width, channels), dtype=np.uint8)  # Draw something (http://stackoverflow.com/a/10032271/562769) xx, yy = np.mgrid[:height, :width] circle = (xx - 100) ** 2 + (yy - 100) ** 2  # Set the RGB values for y in range(img.shape[0]):     for x in range(img.shape[1]):         r, g, b = circle[y][x], circle[y][x], circle[y][x]         img[y][x][0] = r         img[y][x][1] = g         img[y][x][2] = b  # Display the image scipy.misc.imshow(img)  # Save the image scipy.misc.imsave("image.png", img) 

gives