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How do you call a method more than one class up the inheritance chain if it's been overridden by another class along the way?
class Grandfather(object): def __init__(self): pass def do_thing(self): # stuff class Father(Grandfather): def __init__(self): super(Father, self).__init__() def do_thing(self): # stuff different than Grandfather stuff class Son(Father): def __init__(self): super(Son, self).__init__() def do_thing(self): # how to be like Grandfather? 
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Invoking overridden method from sub-class : We can call parent class method in overriding method using super keyword. Overriding and constructor : We can not override constructor as parent and child class can never have constructor with same name(Constructor name must always be same as Class name).
In Python method overriding occurs by simply defining in the child class a method with the same name of a method in the parent class. When you define a method in the object you make this latter able to satisfy that method call, so the implementations of its ancestors do not come in play.
If you override a parent method in its child, child objects will always use the overridden version. But; you can use the keyword super to call the parent method, inside the body of the child method.
If you always want Grandfather#do_thing, regardless of whether Grandfather is Father's immediate superclass then you can explicitly invoke Grandfather#do_thing on the Son self object:
class Son(Father): # ... snip ... def do_thing(self): Grandfather.do_thing(self) On the other hand, if you want to invoke the do_thing method of Father's superclass, regardless of whether it is Grandfather you should use super (as in Thierry's answer):
class Son(Father): # ... snip ... def do_thing(self): super(Father, self).do_thing() If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
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