How do I avoid two filters when condition involves an Optional

Question

I have code like this:

myList.stream()
            .filter(item -> item.getName().isPresent())
            .filter(item -> item.getName().get().equalsIgnoreCase(otherName))
            .findFirst();

(... where item.getName() has a return type of Optional<String>)

How can I condense two filters into one here?

Answer 1

You can use Optional.filter():

myList.stream()
    .filter(item -> 
        item.getName().filter(n -> n.equalsIgnoreCase(otherName)).isPresent())
    .findFirst();

The inner filter call is Optional.filter, which returns an empty optional if the filter condition was not met.

Answer 2

You can avoid it with Optional::stream() method:

If a value is present, returns a sequential Stream containing only that value, otherwise returns an empty Stream.

myList.stream()
  .map(Item::getName)
  .flatMap(Optional::stream)
  .filter(otherName::equalsIgnoreCase)
  .findFirst();