I'm trying to generate a license key with two strings combined both into another one string.
String key1 = "X1X2X3X4..Xn"; //this is for the imei key cellphone
String key2 = "Y1Y2Y3Y4M1M2D1D2H1H2m1m2"; //this is a key to mix with the first one
The result of the combination should be like this:
String result = "D1H1X1X2X3Y2Y4X4X5...XnY3Y1D2m2m1H1H2";
I split my strings every two spaces like this and I save into an array:
String [] key1splited = splitStringEvery(key1, 2);
String [] key2splited = splitStringEvery(key2, 2);
public String[] splitStringEvery(String s, int interval) {
int arrayLength = (int) Math.ceil(((s.length() / (double)interval);
String[] result = new String[arrayLength];
int j = 0;
int lastIndex = result.length - 1;
for (int i = 0; i < lastIndex; i++) {
result[i] = s.substring(j, j + interval);
j += interval;
}
result[lastIndex] = s.substring(j);
return result;
}
How can I make the combination of my strings give me a result that looks like this:
String result = "D1H1X1X2X3Y2Y4X4X5...XnY3Y1D2m2m1H1H2";
I hope someone could give me an idea how to solve this.
I am trying to do something like this, but it is very poor method:
static String res = "";
String[] key1splited = splitStringEvery(key1, 2);
String[] key2splited = splitStringEvery(key2, 2);
for (int i = 0; i < key2splited.length; i++) {
if (key2splited[i].equals("D1")) {
res = key2splited[i];
}
if (key2splited[i].equals("H1")) {
res += key2splited[i];
for (int j = 0; j < key1splited.length; j++) {
if (key1splited[j].equals("X1")) {
res += key1splited[j];
}
if (key1splited[j].equals("X2")) {
res += key1splited[j];
}
if (key1splited[j].equals("X3")) {
res += key1splited[j];
}
}
}
}
And so on, but this isn't a good way to do it because the strings are going to change.
Concatenation is the process of combining two or more strings to form a new string by subsequently appending the next string to the end of the previous strings. In Java, two strings can be concatenated by using the + or += operator, or through the concat() method, defined in the java. lang. String class.
You can also generate a random alphanumeric string of fixed length using streams in Java. A random string is generated by first generating a stream of random numbers of ASCII values for 0-9, a-z and A-Z characters.
Method 1: Using Math. random() Here the function getAlphaNumericString(n) generates a random number of length a string. This number is an index of a Character and this Character is appended in temporary local variable sb.
I think the easiest way you could do this is to separate the tokens out of each key (2-char long tokens like X1, D1 etc.) and then combine the tokens into a single String
.
Further, you shuffle up the String
, extracting random tokens and building the Licence Key:
Random rand = new Random(); // generate Random object only once for efficiency purposes
// ... rest of your code
String getLicenceKey(String key1, String key2){
List<String> tokens = new ArrayList<String>();
// add tokens from key1
for(int i = 0; i < key1.length(); i += 2) {
tokens.add(key1.substring(i, i + 2));
}
// add tokens from key2
for(int i = 0; i < key2.length(); i += 2) {
tokens.add(key2.substring(i, i + 2));
}
// build the random result out of the tokens
StringBuilder result = new StringBuilder();
while(tokens.size() != 0){
int randomPos = rand.nextInt(tokens.size());
result.append(tokens.remove(randomPos));
}
return result.toString();
}
Sample outputs for the inputs you gave:
m2XnD2m1H2X1..Y3Y1Y2Y4M1X2M2D1H1X4X3
H2Y2X4M1M2H1Y3Y1m2X1X2D1m1Xn..X3Y4D2
X1X4X3H2D2H1..M2m2Y3m1Y4M1D1Y1X2XnY2
Sample outputs for key1="A1B1C1", key2="D1E1F1":
D1F1B1A1C1E1
C1A1D1B1E1F1
F1E1B1C1D1A1
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