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How to remove last 7 lines from the csv file using unix commands.
For example -
abc
bffkms
slds
Row started 1
Row started 2
Row started 3
Row started 4
Row started 5
Row started 6
Row started 7
I want to delete the last 7 lines from above file. Please suggest.
306
Remove duplicate lines with uniq If you don't need to preserve the order of the lines in the file, using the sort and uniq commands will do what you need in a very straightforward way. The sort command sorts the lines in alphanumeric order. The uniq command ensures that sequential identical lines are reduced to one.
The uniq command in UNIX is a command line utility for reporting or filtering repeated lines in a file. It can remove duplicates, show a count of occurrences, show only repeated lines, ignore certain characters and compare on specific fields.
You can use head
head -n-7 file
from man page:
-n, --lines=[-]K
print the first K lines instead of the first 10;
with the leading '-', print all but the last K lines of each file
like:
kent$ seq 10|head -n-7
1
2
3
An tac awk combination.
tac | awk 'NR>7' | tac
eks:
seq 1 10 | tac | awk 'NR>7' | tac
1
2
3
Another awk version
awk 'FNR==NR {a++;next} FNR<a-7 ' file{,}
This reads the file twice {,}, first counts line, second prints all but last 7 lines.
32
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