Suppose there are many data frames that need the same operation performed on them. For example:
prefix <- c("Mrs.","Mrs.","Mr","Dr.","Mrs.","Mr.","Mrs.","Ms","Ms","Mr")
measure <- rnorm(10)
df1 <- data.frame(prefix,measure)
df1$gender[df1$prefix=="Mrs."] <- "F"
Would create an indicator variable called gender when the value in the adjacent row was "Mrs.". A general way to loop over string variables in R was adapted from here with the function as.name()
added to remove the quotes from "i":
dflist <- c("df1","df2","df3","df4","df5")
for (i in dflist) {
as.name(i)$gender[as.name(i)$prefix=="Ms."] <- "F"
}
Unfortunately this doesn't work. Any suggestions?
You certainly could! Before you do so, note that you can get the number of rows in your data frame using nrow(stock) . Then, you can create a sequence to loop over from 1:nrow(stock) .
There are three types of loop in R programming: For Loop. While Loop. Repeat Loop.
The single instance example would not really create an indicator in the usual sense since the non-"F" values would be <NA>
and those would not work well within R functions. Both arithmetic operations and logical operations will return . Try this instead:
df1$gender <- ifelse(prefix %in% c("Mrs.", "Ms") , "probably F",
ifelse( prefix=="Dr.", "possibly F", # as is my wife.
"probably not F"))
Then follow @HongDoi's advice to use lists. And do not forget to a) return a full dataframe-object , and b) assign the result to an object name (both of which were illustrated but often forgotten by R-newbs.)
Put all your data frames into a list, and then loop/lapply
over them. It'll be much easier on you in the long run.
dfList <- list(df1=df1, df2=df2, ....)
dfList <- lapply(dfList, function(df) {
df$gender[df$prefix == "Mrs."] <- "F"
df
})
dfList$df1
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