The xml file has this snippet:
<?xml version="1.0"?>
<PC-AssayContainer
xmlns="http://www.ncbi.nlm.nih.gov"
xmlns:xs="http://www.w3.org/2001/XMLSchema-instance"
xs:schemaLocation="http://www.ncbi.nlm.nih.gov ftp://ftp.ncbi.nlm.nih.gov/pubchem/specifications/pubchem.xsd"
>
....
<PC-AnnotatedXRef>
<PC-AnnotatedXRef_xref>
<PC-XRefData>
<PC-XRefData_pmid>17959251</PC-XRefData_pmid>
</PC-XRefData>
</PC-AnnotatedXRef_xref>
</PC-AnnotatedXRef>
I tried to parse it using xpath's global search and also tried with some namespacing:
library('XML')
doc = xmlInternalTreeParse('http://s3.amazonaws.com/tommy_chheng/pubmed/485270.descr.xml')
>xpathApply(doc, "//PC-XRefData_pmid")
list()
attr(,"class")
[1] "XMLNodeSet"
> getNodeSet(doc, "//PC-XRefData_pmid")
list()
attr(,"class")
[1] "XMLNodeSet"
> xpathApply(doc, "//xs:PC-XRefData_pmid", ns="xs")
list()
> xpathApply(doc, "//xs:PC-XRefData_pmid", ns= c(xs = "http://www.w3.org/2001/XMLSchema-instance"))
list()
Shouldn't the xpath match:
<PC-XRefData_pmid>17959251</PC-XRefData_pmid>
Since the default namespace is the NIH one (whose URI is "http://www.ncbi.nlm.nih.gov"), <PC-XRefData_pmid>
(and every other element in your XML document that has no namespace prefix) is in that NIH namespace.
So to match them with an XPath, you need to tell your XPath processor what prefix you're going to use for the NIH namespace, and you need to use that prefix in your XPath.
So, without knowing R, I would try
xpathApply(doc, "//nih:PC-XRefData_pmid",
ns= c(nih = "http://www.ncbi.nlm.nih.gov"))
or else
getNodeSet(doc, "//*[local-name() = 'PC-XRefData_pmid']")
as the latter bypasses namespaces.
Just because the XML document declares the NIH namespace as the default one doesn't mean that the XPath processor will know that. In the XML information model, namespace prefixes are not significant. So when I parse in an XML document, it's not supposed to matter whether the NIH namespace is bound to the "nih:" prefix or the "snizzlefritz:" prefix or the "" (default) prefix. The XML parser or XPath processor is not supposed to have to know what prefix got bound to what namespace in the XML document. Especially since there could be several different prefixes bound to the same namespace at different places in the same document... and vice versa. So if you want to have your XPath expression match an element that's in a namespace, you have to declare that namespace to the XPath processor.
Edit: There are a few caveats, contributed by @Jim Pivarski:
So if "doc" is an instance of a document class, the correct solution is:
xpathApply(xmlRoot(doc), "//nih:PC-XRefData_pmid",
namespaces = c(nih = "http://www.ncbi.nlm.nih.gov"))
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