Sending Requests You can create a request and then send the request with the client when you're ready: use GuzzleHttp\Psr7\Request; $request = new Request('PUT', 'http://httpbin.org/put'); $response = $client->send($request, ['timeout' => 2]);
To send the JSON with payload to the REST API endpoint, you need to enclose the JSON data in the body of the HTTP request and indicate the data type of the request body with the "Content-Type: application/json" request header.
To post a JSON to the server using Python Requests Library, call the requests. post() method and pass the target URL as the first parameter and the JSON data with the json= parameter. The json= parameter takes a dictionary and automatically converts it to a JSON string.
For Guzzle 5, 6 and 7 you do it like this:
use GuzzleHttp\Client;
$client = new Client();
$response = $client->post('url', [
GuzzleHttp\RequestOptions::JSON => ['foo' => 'bar'] // or 'json' => [...]
]);
Docs
The simple and basic way (guzzle6):
$client = new Client([
'headers' => [ 'Content-Type' => 'application/json' ]
]);
$response = $client->post('http://api.com/CheckItOutNow',
['body' => json_encode(
[
'hello' => 'World'
]
)]
);
To get the response status code and the content of the body I did this:
echo '<pre>' . var_export($response->getStatusCode(), true) . '</pre>';
echo '<pre>' . var_export($response->getBody()->getContents(), true) . '</pre>';
For Guzzle <= 4:
It's a raw post request so putting the JSON in the body solved the problem
$request = $this->client->post(
$url,
[
'content-type' => 'application/json'
],
);
$request->setBody($data); #set body!
$response = $request->send();
This worked for me (using Guzzle 6)
$client = new Client();
$result = $client->post('http://api.example.com', [
'json' => [
'value_1' => 'number1',
'Value_group' =>
array("value_2" => "number2",
"value_3" => "number3")
]
]);
echo($result->getBody()->getContents());
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