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What would be a nice way to go from {2:3, 1:89, 4:5, 3:0} to {1:89, 2:3, 3:0, 4:5}?
I checked some posts but they all use the "sorted" operator that returns tuples.
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To sort dictionary key in python we can use dict. items() and sorted(iterable) method. Dict. items() method returns an object that stores key-value pairs of dictionaries.
To sort a list of dictionaries according to the value of the specific key, specify the key parameter of the sort() method or the sorted() function. By specifying a function to be applied to each element of the list, it is sorted according to the result of that function.
To sort a dictionary by value in Python you can use the sorted() function. Python's sorted() function can be used to sort dictionaries by key, which allows for a custom sorting method. sorted() takes three arguments: object, key, and reverse. Dictionaries are unordered data structures.
Standard Python dictionaries are unordered (until Python 3.7). Even if you sorted the (key,value) pairs, you wouldn't be able to store them in a dict in a way that would preserve the ordering.
The easiest way is to use OrderedDict, which remembers the order in which the elements have been inserted:
In [1]: import collections In [2]: d = {2:3, 1:89, 4:5, 3:0} In [3]: od = collections.OrderedDict(sorted(d.items())) In [4]: od Out[4]: OrderedDict([(1, 89), (2, 3), (3, 0), (4, 5)]) Never mind the way od is printed out; it'll work as expected:
In [11]: od[1] Out[11]: 89 In [12]: od[3] Out[12]: 0 In [13]: for k, v in od.iteritems(): print k, v ....: 1 89 2 3 3 0 4 5 For Python 3 users, one needs to use the .items() instead of .iteritems():
In [13]: for k, v in od.items(): print(k, v) ....: 1 89 2 3 3 0 4 5 If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
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