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I would like to do something like this:
for (int p : colourPos[i+1])
How do I skip the first iteration of my colourPos vector?
Can I use .begin() and .end()?
744
Call next() once to discard the first row.
The continue statement in Python is used to skip the rest of the code inside a loop for the current iteration only. In other words, the loop will not terminate immediately but it will continue on with the next iteration. This is in contrast with the break statement which will terminate the loop completely.
You can use a continue statement in Python to skip over part of a loop when a condition is met. Then, the rest of a loop will continue running. You use continue statements within loops, usually after an if statement.
Live demo link.
#include <iostream>
#include <vector>
#include <iterator>
#include <cstddef>
template <typename T>
struct skip
{
T& t;
std::size_t n;
skip(T& v, std::size_t s) : t(v), n(s) {}
auto begin() -> decltype(std::begin(t))
{
return std::next(std::begin(t), n);
}
auto end() -> decltype(std::end(t))
{
return std::end(t);
}
};
int main()
{
std::vector<int> v{ 1, 2, 3, 4 };
for (auto p : skip<decltype(v)>(v, 1))
{
std::cout << p << " ";
}
}
Output:
2 3 4
Or simpler:
Yet another live demo link.
#include <iostream>
#include <vector>
template <typename T>
struct range_t
{
T b, e;
range_t(T x, T y) : b(x), e(y) {}
T begin()
{
return b;
}
T end()
{
return e;
}
};
template <typename T>
range_t<T> range(T b, T e)
{
return range_t<T>(b, e);
}
int main()
{
std::vector<int> v{ 1, 2, 3, 4 };
for (auto p : range(v.begin()+1, v.end()))
{
std::cout << p << " ";
}
}
Output:
2 3 4
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