Is there a way to make setw
and setfill
pad the end of a string instead of the front?
I have a situation where I'm printing something like this.
CONSTANT TEXT variablesizeName1 .....:number1
CONSTANT TEXT varsizeName2 ..........:number2
I want to add a variable amount of '.'
to the end of
"CONSTANT TEXT variablesizeName#"
so I can make ":number#"
line up on the screen.
Note: I have an array of "variablesizeName#"
so I know the widest case.
Or
Should I do it manually by setting setw
like this
for( int x= 0; x < ARRAYSIZE; x++)
{
string temp = string("CONSTANT TEXT ")+variabletext[x];
cout << temp;
cout << setw(MAXWIDTH - temp.length) << setfill('.') <<":";
cout << Number<<"\n";
}
I guess this would do the job but it feels kind of clunky.
Ideas?
You can use manipulators std::left
, std::right
, and std::internal
to choose where the fill characters go.
For your specific case, something like this could do:
#include <iostream>
#include <iomanip>
#include <string>
const char* C_TEXT = "Constant text ";
const size_t MAXWIDTH = 10;
void print(const std::string& var_text, int num)
{
std::cout << C_TEXT
// align output to left, fill goes to right
<< std::left << std::setw(MAXWIDTH) << std::setfill('.')
<< var_text << ": " << num << '\n';
}
int main()
{
print("1234567890", 42);
print("12345", 101);
}
Output:
Constant text 1234567890: 42
Constant text 12345.....: 101
EDIT:
As mentioned in the link, std::internal
works only with integer, floating point and monetary output. For example with negative integers, it'll insert fill characters between negative sign and left-most digit.
This:
int32_t i = -1;
std::cout << std::internal
<< std::setfill('0')
<< std::setw(11) // max 10 digits + negative sign
<< i << '\n';
i = -123;
std::cout << std::internal
<< std::setfill('0')
<< std::setw(11)
<< i;
will output
-0000000001
-0000000123
Something like:
cout << left << setw(MAXWIDTH) << setfill('.') << temp << ':' << Number << endl;
Produces something like:
derp..........................:234
herpderpborp..................:12345678
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