C++ 11 thread simple example

Question

I'm new to c++ and I was looking into some c++ cross-platform thread tutorials. I was looking into this: http://solarianprogrammer.com/2011/12/16/cpp-11-thread-tutorial/

and was trying to execute the following code:

#include <iostream>
#include <thread>

static const int num_threads = 10;

//This function will be called from a thread

void call_from_thread(int tid) {
    std::cout << "Launched by thread " << tid << std::endl;
}

int main() {
    std::thread t[num_threads];

    //Launch a group of threads
    for (int i = 0; i < num_threads; ++i) {
        t[i] = std::thread(call_from_thread, i);
    }

    std::cout << "Launched from the main\n";

    //Join the threads with the main thread
    for (int i = 0; i < num_threads; ++i) {
        t[i].join();
    }

    return 0;
}

The output I'm getting is the following and I can not understand why:

syd@syd-HP-Compaq-dx7500-Microtower:~/Desktop$ ./ref
Launched by thread Launched by thread Launched by thread Launched by thread Launched by thread 201
Launched by thread 5

Launched by thread 6
4
Launched by thread 7
3

Launched by thread 8
Launched from the main
Launched by thread 9

I understand that the numbers are random each time, but some times I get no numbers displayed and I wonder why?

Answer 1

all you need to do is adding a mutex and lock it in the proper position:

std::mutex mtx;

-

void call_from_thread(int tid) {
    mtx.lock();
-----------------------------------------------------------
    std::cout << "Launched by thread " << tid << std::endl;
-----------------------------------------------------------
    mtx.unlock();
}

-

mtx.lock();
-----------------------------------------------------------
std::cout << "Launched from the main\n";
-----------------------------------------------------------
mtx.unlock();

refer to this