I have a list of news items, sorted by dateCreated. I have a preview box control where I only want to show the first item. How can I do that using XSLT?
<xml> <news> <newsitem> <dateCreated>2009-09-09</dateCreated> <summary>Something great happened</sumamry> </newsitem> <newsitem> <dateCreated>2009-09-08</dateCreated> <summary>Something bad happened</sumamry> </newsitem> <newsitem> <dateCreated>2009-09-07</dateCreated> <summary>Something really bad happened</sumamry> </newsitem> </news> </xml>
XSLT doesn't have any new function to search Strings in a reverse manner. We have substring function which creates two fields substring-before-last and substring-after-last.In XSLT it is defined as follows: <xsl:value-of select="substring (string name ,0, MAX_LENGTH )"/>...
This answer is not useful. Show activity on this post. The expression: select="RCODE[1]" means select the first RCODE child.
XSLT <xsl:value-of> Element The <xsl:value-of> element is used to extract the value of a selected node.
If you wish to output XHTML 1.1, here's one way:
<?xml version="1.0"?> <xsl:transform version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xs="http://www.w3.org/2001/XMLSchema" exclude-result-prefixes="xsl xs"> <xsl:output mode="xhtml" version="1.1" omit-xml-declaration="yes" encoding="utf-8" media-type="application/xhtml+xml" indent="no" doctype-public="-//W3C//DTD XHTML 1.1//EN" doctype-system="http://www.w3.org/TR/xhtml11/DTD/xhtml11.dtd" /> <xsl:template match="//newsItem[1]"> <div><xsl:value-of select="dateCreated"/></div> <div><xsl:value-of select="summary"/></div> </xsl:template> </xsl:transform>
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