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How can I select an element in a component template?

Does anybody know how to get hold of an element defined in a component template? Polymer makes it really easy with the $ and $$.

I was just wondering how to go about it in Angular.

Take the example from the tutorial:

import {Component} from '@angular/core';

@Component({
    selector:'display',
    template:`
     <input #myname (input)="updateName(myname.value)"/>
     <p>My name : {{myName}}</p>
     `   
})
export class DisplayComponent {
    myName: string = "Aman";
    updateName(input: String) {
        this.myName = input;
    }
}

How do I catch hold or get a reference of the p or input element from within the class definition?

like image 421
Aman Gupta Avatar asked Sep 21 '15 10:09

Aman Gupta


People also ask

How do you find the element reference?

Getting ElementRef in Component Class Create a template reference variable for the element in the component/directive. Use the template variable to inject the element into component class using the ViewChild or ViewChildren.

What is the use of ElementRef in Angular?

Angular ElementRef is a wrapper around a native element inside of a View. It's simply a class that wraps native DOM elements in the browser and allows you to work with the DOM by providing the nativeElement object which exposes all the methods and properties of the native elements.


13 Answers

Instead of injecting ElementRef and using querySelector or similar from there, a declarative way can be used instead to access elements in the view directly:

<input #myname>
@ViewChild('myname') input; 

element

ngAfterViewInit() {
  console.log(this.input.nativeElement.value);
}

StackBlitz example

  • @ViewChild() supports directive or component type as parameter, or the name (string) of a template variable.
  • @ViewChildren() also supports a list of names as comma separated list (currently no spaces allowed @ViewChildren('var1,var2,var3')).
  • @ContentChild() and @ContentChildren() do the same but in the light DOM (<ng-content> projected elements).

descendants

@ContentChildren() is the only one that allows to also query for descendants

@ContentChildren(SomeTypeOrVarName, {descendants: true}) someField; 

{descendants: true} should be the default but is not in 2.0.0 final and it's considered a bug
This was fixed in 2.0.1

read

If there are a component and directives the read parameter allows to specify which instance should be returned.

For example ViewContainerRef that is required by dynamically created components instead of the default ElementRef

@ViewChild('myname', { read: ViewContainerRef }) target;

subscribe changes

Even though view children are only set when ngAfterViewInit() is called and content children are only set when ngAfterContentInit() is called, if you want to subscribe to changes of the query result, it should be done in ngOnInit()

https://github.com/angular/angular/issues/9689#issuecomment-229247134

@ViewChildren(SomeType) viewChildren;
@ContentChildren(SomeType) contentChildren;

ngOnInit() {
  this.viewChildren.changes.subscribe(changes => console.log(changes));
  this.contentChildren.changes.subscribe(changes => console.log(changes));
}

direct DOM access

can only query DOM elements, but not components or directive instances:

export class MyComponent {
  constructor(private elRef:ElementRef) {}
  ngAfterViewInit() {
    var div = this.elRef.nativeElement.querySelector('div');
    console.log(div);
  }

  // for transcluded content
  ngAfterContentInit() {
    var div = this.elRef.nativeElement.querySelector('div');
    console.log(div);
  }
}

get arbitrary projected content

See Access transcluded content

like image 111
Günter Zöchbauer Avatar answered Oct 21 '22 13:10

Günter Zöchbauer


You can get a handle to the DOM element via ElementRef by injecting it into your component's constructor:

constructor(private myElement: ElementRef) { ... }

Docs: https://angular.io/docs/ts/latest/api/core/index/ElementRef-class.html

like image 44
Brocco Avatar answered Oct 21 '22 13:10

Brocco


import { Component, ElementRef, OnInit } from '@angular/core';

@Component({
  selector:'display',
  template:`
   <input (input)="updateName($event.target.value)">
   <p> My name : {{ myName }}</p>
  `
})
class DisplayComponent implements OnInit {
  constructor(public element: ElementRef) {
    this.element.nativeElement // <- your direct element reference 
  }
  ngOnInit() {
    var el = this.element.nativeElement;
    console.log(el);
  }
  updateName(value) {
    // ...
  }
}

Example updated to work with the latest version

For more details on native element, here

like image 27
gdi2290 Avatar answered Oct 21 '22 12:10

gdi2290


Angular 4+: Use renderer.selectRootElement with a CSS selector to access the element.

I've got a form that initially displays an email input. After the email is entered, the form will be expanded to allow them to continue adding information relating to their project. However, if they are not an existing client, the form will include an address section above the project information section.

As of now, the data entry portion has not been broken up into components, so the sections are managed with *ngIf directives. I need to set focus on the project notes field if they are an existing client, or the first name field if they are new.

I tried the solutions with no success. However, Update 3 in this answer gave me half of the eventual solution. The other half came from MatteoNY's response in this thread. The result is this:

import { NgZone, Renderer } from '@angular/core';

constructor(private ngZone: NgZone, private renderer: Renderer) {}

setFocus(selector: string): void {
    this.ngZone.runOutsideAngular(() => {
        setTimeout(() => {
            this.renderer.selectRootElement(selector).focus();
        }, 0);
    });
}

submitEmail(email: string): void {
    // Verify existence of customer
    ...
    if (this.newCustomer) {
        this.setFocus('#firstname');
    } else {
        this.setFocus('#description');
    }
}

Since the only thing I'm doing is setting the focus on an element, I don't need to concern myself with change detection, so I can actually run the call to renderer.selectRootElement outside of Angular. Because I need to give the new sections time to render, the element section is wrapped in a timeout to allow the rendering threads time to catch up before the element selection is attempted. Once all that is setup, I can simply call the element using basic CSS selectors.

I know this example dealt primarily with the focus event, but it's hard for me that this couldn't be used in other contexts.

UPDATE: Angular dropped support for Renderer in Angular 4 and removed it completely in Angular 9. This solution should not be impacted by the migration to Renderer2. Please refer to this link for additional information: Renderer migration to Renderer2

like image 25
Neil T. Avatar answered Oct 21 '22 11:10

Neil T.


For people trying to grab the component instance inside a *ngIf or *ngSwitchCase, you can follow this trick.

Create an init directive.

import {
    Directive,
    EventEmitter,
    Output,
    OnInit,
    ElementRef
} from '@angular/core';

@Directive({
    selector: '[init]'
})
export class InitDirective implements OnInit {
    constructor(private ref: ElementRef) {}

    @Output() init: EventEmitter<ElementRef> = new EventEmitter<ElementRef>();

    ngOnInit() {
        this.init.emit(this.ref);
    }
}

Export your component with a name such as myComponent

@Component({
    selector: 'wm-my-component',
    templateUrl: 'my-component.component.html',
    styleUrls: ['my-component.component.css'],
    exportAs: 'myComponent'
})
export class MyComponent { ... }

Use this template to get the ElementRef AND MyComponent instance

<div [ngSwitch]="type">
    <wm-my-component
           #myComponent="myComponent"
           *ngSwitchCase="Type.MyType"
           (init)="init($event, myComponent)">
    </wm-my-component>
</div>

Use this code in TypeScript

init(myComponentRef: ElementRef, myComponent: MyComponent) {
}
like image 35
jsgoupil Avatar answered Oct 21 '22 12:10

jsgoupil


import the ViewChild decorator from @angular/core, like so:

HTML Code:

<form #f="ngForm"> 
  ... 
  ... 
</form>

TS Code:

import { ViewChild } from '@angular/core';

class TemplateFormComponent {

  @ViewChild('f') myForm: any;
    .
    .
    .
}

now you can use 'myForm' object to access any element within it in the class.

Source

like image 28
Hany Avatar answered Oct 21 '22 11:10

Hany


 */
import {Component,ViewChild} from '@angular/core' /*Import View Child*/

@Component({
    selector:'display'
    template:`

     <input #myname (input) = "updateName(myname.value)"/>
     <p> My name : {{myName}}</p>

    `
})
export class DisplayComponent{
  @ViewChild('myname')inputTxt:ElementRef; /*create a view child*/

   myName: string;

    updateName: Function;
    constructor(){

        this.myName = "Aman";
        this.updateName = function(input: String){

            this.inputTxt.nativeElement.value=this.myName; 

            /*assign to it the value*/
        };
    }
}
like image 29
Mohamed Gabr Avatar answered Oct 21 '22 12:10

Mohamed Gabr


I have used two way:

First way :

You can get a handle to the DOM element via ElementRef by injecting it into your component's constructor:

constructor(private myElement: ElementRef) {
this.myElement.nativeElement // <- your direct element reference
}

Second way:

@Component({
  selector: 'my-app',
  template:
  `
  <input #input value="enterThere">
  `,
  styleUrls: [ './app.component.css' ]
})
export class AppComponent  {
  @ViewChild('input') input:ElementRef; 

  ngAfterViewInit() {
    console.log(this.input);
  }
like image 28
Naeem Bashir Avatar answered Oct 21 '22 13:10

Naeem Bashir


Note: This doesn't apply to Angular 6 and above as ElementRef became ElementRef<T> with T denoting the type of nativeElement.

I would like to add that if you are using ElementRef, as recommended by all answers, then you will immediately encounter the problem that ElementRef has an awful type declaration that looks like

export declare class ElementRef {
  nativeElement: any;
}

this is stupid in a browser environment where nativeElement is an HTMLElement.

To workaround this you can use the following technique

import {Inject, ElementRef as ErrorProneElementRef} from '@angular/core';

interface ElementRef {
  nativeElement: HTMLElement;
}

@Component({...}) export class MyComponent {
  constructor(@Inject(ErrorProneElementRef) readonly elementRef: ElementRef) { }
}
like image 22
Aluan Haddad Avatar answered Oct 21 '22 12:10

Aluan Haddad


Mimimum example for quick usage:

import { Component, ElementRef, ViewChild} from '@angular/core';

@Component({
  selector: 'my-app',
  template:
  `
  <input #inputEl value="hithere">
  `,
  styleUrls: [ './app.component.css' ]
})
export class AppComponent  {
  @ViewChild('inputEl') inputEl:ElementRef; 

  ngAfterViewInit() {
    console.log(this.inputEl);
  }
}
  1. Put a template reference variable on the DOM element of interest. In our example this is the #inputEl on the <input> tag.
  2. In our component class inject the DOM element via the @ViewChild decorator
  3. Access the element in the ngAfterViewInit lifecycle hook.

Note:

If you want to manipulate the DOM elements use the Renderer2 API instead of accessing the elements directly. Permitting direct access to the DOM can make your application more vulnerable to XSS attacks

like image 24
Willem van der Veen Avatar answered Oct 21 '22 12:10

Willem van der Veen


to get the immediate next sibling ,use this

event.source._elementRef.nativeElement.nextElementSibling
like image 32
Apoorv Avatar answered Oct 21 '22 13:10

Apoorv


Selecting target element from the list. It is easy to select particular element from the list of same elements.

component code:

export class AppComponent {
  title = 'app';

  listEvents = [
    {'name':'item1', 'class': ''}, {'name':'item2', 'class': ''},
    {'name':'item3', 'class': ''}, {'name':'item4', 'class': ''}
  ];

  selectElement(item: string, value: number) {
    console.log("item="+item+" value="+value);
    if(this.listEvents[value].class == "") {
      this.listEvents[value].class='selected';
    } else {
      this.listEvents[value].class= '';
    }
  }
}

html code:

<ul *ngFor="let event of listEvents; let i = index">
   <li  (click)="selectElement(event.name, i)" [class]="event.class">
  {{ event.name }}
</li>

css code:

.selected {
  color: red;
  background:blue;
}
like image 37
Sai Goud Avatar answered Oct 21 '22 12:10

Sai Goud


For components inside *ngIf, another approach:

The component I wanted to select was inside a div's *ngIf statement, and @jsgoupil's answer above probably works (Thanks @jsgoupil!), but I ended up finding a way to avoid using *ngIf, by using CSS to hide the element.

When the condition in the [className] is true, the div gets displayed, and naming the component using # works and it can be selected from within the typescript code. When the condition is false, it's not displayed, and I don't need to select it anyway.

Component:

@Component({
    selector: 'bla',
    templateUrl: 'bla.component.html',
    styleUrls: ['bla.component.scss']
})
export class BlaComponent implements OnInit, OnDestroy {
    @ViewChild('myComponentWidget', {static: true}) public myComponentWidget: any;
    @Input('action') action: ActionType; // an enum defined in our code. (action could also be declared locally)

constructor() {
   etc;
}

// this lets you use an enum in the HMTL (ActionType.SomeType)
public get actionTypeEnum(): typeOf ActionType {
    return ActionType;
}

public someMethodXYZ: void {
    this.myComponentWidget.someMethod(); // use it like that, assuming the method exists
}

and then in the bla.component.html file:

<div [className]="action === actionTypeEnum.SomeType ? 'show-it' : 'do-not-show'">

    <my-component #myComponentWidget etc></my-component>
</div>
<div>
    <button type="reset" class="bunch-of-classes" (click)="someMethodXYZ()">
        <span>XYZ</span>
    </button>
</div>   

and the CSS file:

 ::ng-deep {
    .show-it {
         display: block;   // example, actually a lot more css in our code
    }
    .do-not-show {
        display: none'; 
    }
}
like image 23
TomEberhard Avatar answered Oct 21 '22 11:10

TomEberhard