The following bit of code does exactly what I want, except it only prints to the console.
cmd := exec.Command("php", "randomcommand.php")
cmd.Stdout = os.Stdout
cmd.Stderr = os.Stderr
if err := cmd.Run(); err != nil {
log.Fatal(err)
}
randomcommand.php:
// randomcommand.php simply alternates output between stdout and stderr 20 times
$stdout = fopen('php://stdout', 'w+');
$stderr = fopen('php://stderr', 'w+');
for ($i = 1;$i <= 20; $i++) {
fwrite($stdout, "stdout $i\n");
fwrite($stderr, "stderr $i\n");
}
Output:
stdout 1
stderr 1
stdout 2
stderr 2
stdout 3
stderr 3
stdout 4
stderr 4
stdout 5
stderr 5
stdout 6
stderr 6
stdout 7
stderr 7
stdout 8
stderr 8
stdout 9
stderr 9
stdout 10
stderr 10
stdout 11
stderr 11
stdout 12
stderr 12
stdout 13
stderr 13
stdout 14
stderr 14
stdout 15
stderr 15
stdout 16
stderr 16
stdout 17
stderr 17
stdout 18
stderr 18
stdout 19
stderr 19
stdout 20
stderr 20
What I'm trying to achieve is:
I've tried piping the command stdout and stderr into scanners or using io.Copy, each in a goroutine, but order of the output was not maintained. Probably because alternating between goroutines would have to occur at the same time as output alternates, which is just about impossible.
I also tried the using "select" as in the examples from here. But order of output was not maintained.
Same problem with Logstreamer.
The other idea I have to try is to see if I can somehow just read from the console buffer, but this just doesn't feel right.
Does anyone know if this is even possible and worth pursuing?
You can redirect stderr to stdout by using 2>&1 , and then pipe stdout into grep . what does &1 means? To specify redirection to existing handles, use the ampersand & character followed by the handle number that you want to redirect (that is, &handle# ). stdin is handle #0, stdout is handle #1, and stderr is handle #2.
Use the shell syntax to redirect standard error messages to the same place as standard output. where both is just our (imaginary) program that is going to generate output to both STDERR and STDOUT.
In bash, calling foo would display any output from that command on the stdout. Calling foo > output would redirect any output from that command to the file specified (in this case 'output').
As I said in the comment section, this can be achieved using MultiWriter
package main
import (
"io"
"log"
"os"
"os/exec"
)
func main() {
// Logging capability
f, err := os.OpenFile("log.log", os.O_RDWR|os.O_CREATE|os.O_APPEND, 0666)
if err != nil {
log.Fatalf("Error opening file: %v", err)
}
defer f.Close()
mwriter := io.MultiWriter(f, os.Stdout)
cmd := exec.Command("ls")
cmd.Stderr = mwriter
cmd.Stdout = mwriter
err = cmd.Run() //blocks until sub process is complete
if err != nil {
panic(err)
}
}
When you declare your command, and before you run it, just specify that Stdout and Stderr are using the MultiWriter defined above. This MultiWriter instance contains both a log file and the standard output.
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