How can I pattern match on a range in Scala?

Question

In Ruby I can write this:

case n when 0...5  then "less than five" when 5...10 then "less than ten" else "a lot" end 

How do I do this in Scala?

Edit: preferably I'd like to do it more elegantly than using if.

Answer 1

Inside pattern match it can be expressed with guards:

n match {   case it if 0 until 5 contains it  => "less than five"   case it if 5 until 10 contains it => "less than ten"   case _ => "a lot" }