How do I expose Scala constructor arguments as public members?

Question

Look at this example:

class Point(x: Double, y: Double){   override def toString = "x: " + x + ", y: " + y   def +(sourcePoint: Point) : Point = {     return new Point(x + sourcePoint.x, y + sourcePoint.y   } } 

As you can see I want to define a + operator method on the Point class. But this won't work because in that method, x and y can't be accessed on the sourcePoint local variable since they are private, so I changed the example into this:

class Point(_x: Double, _y: Double){   var x = _x   var y = _y    override def toString = "x: " + x + ", y: " + y   def +(sourcePoint: Point) : Point = {     return new Point(x + sourcePoint.x, y + sourcePoint.y)   } } 

That obviously worked, however is there an easier way to define these variables instead of going from _x -> x and _y -> y.

Thanks for help and time! :)

Answer 1

Yes, there is:

class Point(val x: Int, val y: Int) 

Answer 2

using val is valid but then the parameter becomes final (constant). If you want to be able to reassign the value you should use var instead. So

class Point(var x: Int, var y: Int)