How can I obtain the identifier of the current function?

Question

In C/C++, we have the __FUNCTION__ macro which is replaced with a string, holding the name of the current function. But what if I want the function's identifier? That is, not a string, but something I could use as a token to create other identifiers, e.g., if we have

#define MAGIC /* ... */

#define MORE_MAGIC MAGIC ## _bar

void foo() {
    printf("%s\n",__FUNCTION__);
    MORE_MAGIC();
}

void foo_bar() {
    printf("%s\n",__FUNCTION__);
}

void baz() {
    printf("%s\n",__FUNCTION__);
    MORE_MAGIC();
}

void baz_bar() {
    printf("%s\n",__FUNCTION__);
}

int main() {
    foo();
}

should print

foo
foo_bar
baz
baz_bar

---

Notes:

• I'm interested in preprocessing-time only.
• I would rather not replace my function definitions with a preprocessor call - although I know that would probably work.

Answer 1

Unfortunately you can't. Because you can not unstringify a macro[1].

In other words, you can not remove quotes around the string that generated by __FUNCTION__ and contact it by _bar.

Answer 2

If it's compile-time you want, and for a simple case like your, it might be possible with preprocessor macros and the concatenation operator ##. Maybe something like

#define MORE_MAGIC(f) f##_bar

...

void foo_bar()
{
}

void foo()
{
    MORE_MAGIC(foo)();
}

It's not possible to get the name foo automatically though, it has to be explicitly named in the macro "call".