I have a range based for loop to iterate over elements in foobar
as follows:
#include <map>
#include <iostream>
int main()
{
std::map<int, int> foobar({{1,1}, {2,2}, {3,3}});
for(auto p : foobar)
{
++p.second;
std::cout << "{" << p.first << ", " << p.second << "} ";
}
std::cout << std::endl;
for(auto q : foobar)
{
std::cout << "{" << q.first << ", " << q.second << "} ";
}
std::cout << std::endl;
}
This code produces the following output:
{1, 2} {2, 3} {3, 4}
{1, 1} {2, 2} {3, 3}
The first line is modified and printed inside a for loop and the second line supposedly prints the same modified values. Why don't the outputs match? Are changes to std::map
only effective in the scope of the loop? Is there a way I can not only access but modify these values?
A running version of this code can be found on cpp.sh.
EDIT: The example given here was modified to match the accepted answer for clarity.
You can turn auto
into auto&
if you want to mutate/modify the container, for instance:
#include <map>
#include <iostream>
int main()
{
std::map<int, int> foobar({{1,1}, {2,2}, {3,3}});
for(auto& p : foobar) {
++p.second;
std::cout << '{' << p.first << ", " << p.second << "} ";
}
std::cout << std::endl;
}
compiles ands outputs
{1, 2} {2, 3} {3, 4}
live example
Plain auto
is by value (you get a copy). Use auto&
.
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