I have the following loop to calculate the dates of the current week and print them out. It works, but I am swimming in the amount of date/time possibilities in Perl and want to get your opinion on whether there is a better way. Here's the code I've written:
#!/usr/bin/env perl
use warnings;
use strict;
use DateTime;
# Calculate numeric value of today and the
# target day (Monday = 1, Sunday = 7); the
# target, in this case, is Monday, since that's
# when I want the week to start
my $today_dt = DateTime->now;
my $today = $today_dt->day_of_week;
my $target = 1;
# Create DateTime copies to act as the "bookends"
# for the date range
my ($start, $end) = ($today_dt->clone(), $today_dt->clone());
if ($today == $target)
{
# If today is the target, "start" is already set;
# we simply need to set the end date
$end->add( days => 6 );
}
else
{
# Otherwise, we calculate the Monday preceeding today
# and the Sunday following today
my $delta = ($target - $today + 7) % 7;
$start->add( days => $delta - 7 );
$end->add( days => $delta - 1 );
}
# I clone the DateTime object again because, for some reason,
# I'm wary of using $start directly...
my $cur_date = $start->clone();
while ($cur_date <= $end)
{
my $date_ymd = $cur_date->ymd;
print "$date_ymd\n";
$cur_date->add( days => 1 );
}
As mentioned, this works, but is it the quickest or most efficient? I'm guessing that quickness and efficiency may not necessarily go together, but your feedback is very appreciated.
$year += 1900; To get the last two digits of the year (e.g., "01" in 2001) do: $year = sprintf("%02d", $year % 100); $wday is the day of the week, with 0 indicating Sunday and 3 indicating Wednesday.
localtime() function in Perl returns the current date and time of the system, if called without passing any argument.
If you want yesterday's date: use DateTime qw( ); my $yday_date = DateTime ->now( time_zone => 'local' ) ->set_time_zone('floating') ->truncate( to => 'day' ) ->subtract( days => 1 ) ->strftime('%Y-%m-%d'); For example, in New York on 2019-05-14 at 01:00:00, it would have returned 2019-05-13.
There is a strange scalar variable called $_ in Perl, which is the default variable, or in other words the topic. In Perl, several functions and operators use this variable as a default, in case no parameter is explicitly used.
A slightly improved version of friedo's answer ...
my $start_of_week =
DateTime->today()
->truncate( to => 'week' );
for ( 0..6 ) {
print $start_of_week->clone()->add( days => $_ );
}
However, this assumes that Monday is the first day of the week. For Sunday, start with ...
my $start_of_week =
DateTime->today()
->truncate( to => 'week' )
->subtract( days => 1 );
Either way, it's better to use the truncate
method than re-implement it, as friedo did ;)
You can use the DateTime object to get the current day of the week as a number ( 1-7 ). Then just use that to find the current week's Monday. For example:
my $today = DateTime->now;
my $start = $today->clone;
# move $start to Monday
$start->subtract( days => ( $today->wday - 1 ) ); # Monday gives 1, so on monday we
# subtract zero.
my $end = $start->clone->add( days => 7 );
The above is untested but the idea should work.
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With