How can I get the index of an item in a list in a single step?

Question

How about the List.FindIndex Method:

int index = myList.FindIndex(a => a.Prop == oProp);

This method performs a linear search; therefore, this method is an O(n) operation, where n is Count.

If the item is not found, it will return -1

For simple types you can use "IndexOf":

List<string> arr = new List<string>();
arr.Add("aaa");
arr.Add("bbb");
arr.Add("ccc");
int i = arr.IndexOf("bbb"); // Returns 1.

EDIT: If you're only using a List<> and you only need the index, then List.FindIndex is indeed the best approach. I'll leave this answer here for those who need anything different (e.g. on top of any IEnumerable<>).

Use the overload of Select which takes an index in the predicate, so you transform your list into an (index, value) pair:

var pair = myList.Select((Value, Index) => new { Value, Index })
                 .Single(p => p.Value.Prop == oProp);

Then:

Console.WriteLine("Index:{0}; Value: {1}", pair.Index, pair.Value);

Or if you only want the index and you're using this in multiple places, you could easily write your own extension method which was like Where, but instead of returning the original items, it returned the indexes of those items which matched the predicate.

If you don't want to use LINQ, then:

int index;
for (int i = 0; i < myList.Count; i++)
{
    if (myList[i].Prop == oProp)
    {
       index = i;
       break;
    }
}

This way you are iterating the list only once.