How can I get the href attribute value out of an <?xml-stylesheet> node?

Question

We are getting an XML document from a vendor that we need to perform an XSL transform on using their stylesheet so that we can convert the resulting HTML to a PDF. The actual stylesheet is referenced in an href attribute of the ?xml-stylesheet definition in the XML document. Is there any way that I can get that URL out using C#? I don't trust the vendor not to change the URL and obviously don't want to hardcode it.

The start of the XML file with the full ?xml-stylesheet element looks like this:

<?xml version="1.0" encoding="utf-8"?>
<?xml-stylesheet type="text/xsl" href="http://www.fakeurl.com/StyleSheet.xsl"?>

Answer 1

As a processing instruction can have any contents it formally does not have any attributes. But if you know there are "pseudo" attributes, like in the case of an xml-stylesheet processing instruction, then you can of course use the value of the processing instruction to construct the markup of a single element and parse that with the XML parser:

    XmlDocument doc = new XmlDocument();
    doc.Load(@"file.xml");
    XmlNode pi = doc.SelectSingleNode("processing-instruction('xml-stylesheet')");
    if (pi != null)
    {
        XmlElement piEl = (XmlElement)doc.ReadNode(XmlReader.Create(new StringReader("<pi " + pi.Value + "/>")));
        string href = piEl.GetAttribute("href");
        Console.WriteLine(href);
    }
    else
    {
        Console.WriteLine("No pi found.");
    }