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How can I generate all possible IPs from a list of ip ranges in Python?

Let's say I have a text file contains a bunch of ip ranges like this:

x.x.x.x-y.y.y.y
x.x.x.x-y.y.y.y
x.x.x.x-y.y.y.y
x.x.x.x-y.y.y.y
x.x.x.x-y.y.y.y

x.x.x.x is start value and y.y.y.y is end value of range.

How can I convert these ip ranges to all possible IPs in a new text file in python?

PS: This question is not same as any of my previous questions. I asked "how to generate all possible ips from cidr notations" in my previous question. But in here I ask "how to generate from ip range list". These are different things.

like image 228
Someone Avatar asked Nov 30 '22 12:11

Someone


1 Answers

This function returns all ip addresses like from start to end:

def ips(start, end):
    import socket, struct
    start = struct.unpack('>I', socket.inet_aton(start))[0]
    end = struct.unpack('>I', socket.inet_aton(end))[0]
    return [socket.inet_ntoa(struct.pack('>I', i)) for i in range(start, end)]

These are the building blocks to build it on your own:

>>> import socket, struct
>>> ip = '0.0.0.5'
>>> i = struct.unpack('>I', socket.inet_aton(ip))[0]
>>> i
5
>>> i += 1
>>> socket.inet_ntoa(struct.pack('>I', i))
'0.0.0.6'

Example:

ips('1.2.3.4', '1.2.4.5')
['1.2.3.4', '1.2.3.5', '1.2.3.6', '1.2.3.7', ..., '1.2.3.253', '1.2.3.254', '1.2.3.255', '1.2.4.0', '1.2.4.1', '1.2.4.2', '1.2.4.3', '1.2.4.4']

Read from file

In your case you can read from a file like this:

with open('file') as f:
    for line in f:
        start, end = line.strip().split('-')
        # ....
like image 93
User Avatar answered Dec 04 '22 04:12

User