To retrieve a file in Python, you need to know the exact path to reach the file, in Windows, you can view a particular file's path by right-clicking the File-> Properties-> General-> Location. Similarly, to run a script, the working directory needs to be set to the directory containing the script.
split() method in Python is used to Split the path name into a pair head and tail. Here, tail is the last path name component and head is everything leading up to that. In the above example 'file. txt' component of path name is tail and '/home/User/Desktop/' is head.
You were almost there with your use of the split
function. You just needed to join the strings, like follows.
>>> import os
>>> '\\'.join(existGDBPath.split('\\')[0:-1])
'T:\\Data\\DBDesign'
Although, I would recommend using the os.path.dirname
function to do this, you just need to pass the string, and it'll do the work for you. Since, you seem to be on windows, consider using the abspath
function too. An example:
>>> import os
>>> os.path.dirname(os.path.abspath(existGDBPath))
'T:\\Data\\DBDesign'
If you want both the file name and the directory path after being split, you can use the os.path.split
function which returns a tuple, as follows.
>>> import os
>>> os.path.split(os.path.abspath(existGDBPath))
('T:\\Data\\DBDesign', 'DBDesign_93_v141b.mdb')
WITH PATHLIB MODULE (UPDATED ANSWER)
One should consider using pathlib for new development. It is in the stdlib for Python3.4, but available on PyPI for earlier versions. This library provides a more object-orented method to manipulate paths <opinion>
and is much easier read and program with </opinion>
.
>>> import pathlib
>>> existGDBPath = pathlib.Path(r'T:\Data\DBDesign\DBDesign_93_v141b.mdb')
>>> wkspFldr = existGDBPath.parent
>>> print wkspFldr
Path('T:\Data\DBDesign')
WITH OS MODULE
Use the os.path module:
>>> import os
>>> existGDBPath = r'T:\Data\DBDesign\DBDesign_93_v141b.mdb'
>>> wkspFldr = os.path.dirname(existGDBPath)
>>> print wkspFldr
'T:\Data\DBDesign'
You can go ahead and assume that if you need to do some sort of filename manipulation it's already been implemented in os.path
. If not, you'll still probably need to use this module as the building block.
The built-in submodule os.path has a function for that very task.
import os
os.path.dirname('T:\Data\DBDesign\DBDesign_93_v141b.mdb')
Here is the code:
import os
existGDBPath = r'T:\Data\DBDesign\DBDesign_93_v141b.mdb'
wkspFldr = os.path.dirname(existGDBPath)
print wkspFldr # T:\Data\DBDesign
Here is my little utility helper for splitting paths int file, path tokens:
import os
# usage: file, path = splitPath(s)
def splitPath(s):
f = os.path.basename(s)
p = s[:-(len(f))-1]
return f, p
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With