How can I exclude directories from grep -R?

Question

I want to traverse all subdirectories, except the "node_modules" directory.

Answer 1

Recent versions of GNU Grep (>= 2.5.2) provide:

--exclude-dir=dir 

which excludes directories matching the pattern dir from recursive directory searches.

So you can do:

grep -R --exclude-dir=node_modules 'some pattern' /path/to/search 

For a bit more information regarding syntax and usage see

• The GNU man page for File and Directory Selection
• A related StackOverflow answer Use grep --exclude/--include syntax to not grep through certain files

For older GNU Greps and POSIX Grep, use find as suggested in other answers.

Or just use ack (Edit: or The Silver Searcher) and be done with it!

Answer 2

SOLUTION 1 (combine find and grep)

The purpose of this solution is not to deal with grep performance but to show a portable solution : should also work with busybox or GNU version older than 2.5.

Use find, for excluding directories foo and bar :

find /dir \( -name foo -prune \) -o \( -name bar -prune \) -o -name "*.sh" -print 

Then combine find and the non-recursive use of grep, as a portable solution :

find /dir \( -name node_modules -prune \) -o -name "*.sh" -exec grep --color -Hn "your text to find" {} 2>/dev/null \; 

SOLUTION 2 (using the --exclude-dir option of grep):

You know this solution already, but I add it since it's the most recent and efficient solution. Note this is a less portable solution but more human-readable.

grep -R --exclude-dir=node_modules 'some pattern' /path/to/search 

To exclude multiple directories, use --exclude-dir as:

--exclude-dir={node_modules,dir1,dir2,dir3}

SOLUTION 3 (Ag)

If you frequently search through code, Ag (The Silver Searcher) is a much faster alternative to grep, that's customized for searching code. For instance, it automatically ignores files and directories listed in .gitignore, so you don't have to keep passing the same cumbersome exclude options to grep or find.