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How can I delete a repeated dictionary in list?

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python

for dynamic values sometimes the value will be keep repeating, say if a variable

table = [
    {'man':'tim','age':'2','h':'5','w':'40'},
    {'man':'jim','age':'4','h':'3','w':'20'},
    {'man':'jon','age':'24','h':'5','w':'80'}, 
    {'man':'tim','age':'2','h':'5','w':'40'},
    {'man':'tto','age':'7','h':'4','w':'49'}    
]

here {'man':'tim','age':'2','h':'5','w':'40'} dictionary set repeat twice these are dynamic value.

How can I stop repeating this, so list will not contain any repeated dictionary before rendering it to templates?

edited: actual data

[{'scorecardid': 1, 'progress2': 'preview', 'series2': 'Afghanistan v Zimbabwe in UAE, 2018', 'Commentary1': '/Commentary1', 'commentaryid': 1, 'matchid2': '10', 'matchno2': '5th ODI', 'teams2': 'AFG vs ZIM', 'matchtype2': 'ODI', 'Scorecard1': '/Scorecard1', 'status2': 'Starts on Feb 19 at 10:30 GMT'}, {'six2': '0', 'scorecardid': 2, 'overs5': '4', 'fours1': '0', 'overs10': '20', 'Batting_team_img': 'images/RSA.png', 'wickets20': '5', 'wickets6': '1', 'Bowling_team_img': 'images/IND.png', 'maidens6': '0', 'Batting team': 'RSA', 'matchid2': '9', 'name6': 'Unadkat', 'teams2': 'RSA vs IND', 'wickets10': '9', 'desc10': 'Inns', 'runs5': '32', 'matchtype2': 'T20', 'Scorecard1': '/Scorecard2', 'runs1': '2', 'wickets5': '0', 'runs6': '33', 'runs2': '0', 'maidens5': '0', 'runs20': '203', 'name5': 'Bumrah*', 'progress2': 'complete', 'Commentary1': '/Commentary2', 'fours2': '0', 'series2': 'India tour of South Africa, 2017-18', 'name1': 'Junior Dala*', 'commentaryid': 2, 'matchno2': '1st T20I', 'six1': '0', 'overs6': '4', 'Bowling team': 'IND', 'balls2': '2', 'balls1': '3', 'name2': 'Shamsi', 'overs20': '20', 'runs10': '175', 'desc20': 'Inns', 'status2': 'Ind won by 28 runs'}, {'scorecardid': 3, 'overs5': '0.4', 'fours1': '0', 'overs10': '18.4', 'Batting_team_img': 'images/BAN.png', 'wickets20': '4', 'wickets6': '1', 'Bowling_team_img': 'images/SL.png', 'Batting team': 'BAN', 'matchid2': '6', 'name6': 'Shanaka', 'teams2': 'BAN vs SL', 'wickets10': '10', 'desc10': 'Inns', 'runs5': '3', 'matchtype2': 'T20', 'Scorecard1': '/Scorecard3', 'runs1': '1', 'wickets5': '2', 'runs6': '5', 'maidens5': '0', 'runs20': '210', 'progress2': 'complete', 'Commentary1': '/Commentary3', 'name5': 'Gunathilaka*', 'series2': 'Sri Lanka tour of Bangladesh, 2018', 'name1': 'Nazmul Islam', 'commentaryid': 3, 'matchno2': '2nd T20I', 'six1': '0', 'overs6': '1.5', 'Bowling team': 'SL', 'maidens6': '0', 'balls1': '1', 'overs20': '20', 'runs10': '135', 'desc20': 'Inns', 'status2': 'SL won by 75 runs'}, {'six2': '2', 'scorecardid': 4, 'overs5': '4', 'fours1': '1', 'overs10': '20', 'Batting_team_img': 'images/NZ.png', 'wickets20': '7', 'wickets6': '1', 'Bowling_team_img': 'images/ENG.png', 'maidens6': '0', 'Batting team': 'NZ', 'matchid2': '4', 'name6': 'Tom Curran', 'teams2': 'NZ vs ENG', 'wickets10': '4', 'desc10': 'Inns', 'runs5': '41', 'matchtype2': 'T20', 'Scorecard1': '/Scorecard4', 'runs1': '7', 'wickets5': '0', 'runs6': '32', 'runs2': '37', 'maidens5': '0', 'runs20': '194', 'name5': 'Chris Jordan*', 'progress2': 'complete', 'Commentary1': '/Commentary4', 'fours2': '2', 'series2': 'England, Australia, New Zealand T20I Tri-Series, 2018', 'name1': 'de Grandhomme*', 'commentaryid': 4, 'matchno2': '6th Match', 'six1': '0', 'overs6': '3', 'Bowling team': 'ENG', 'balls2': '30', 'balls1': '5', 'name2': 'Chapman', 'overs20': '20', 'runs10': '192', 'desc20': 'Inns', 'status2': 'Eng won by 2 runs'}, {'scorecardid': 5, 'overs5': '7.4', 'fours1': '3', 'runs20': '213', 'six2': '0', 'commentaryid': 5, 'Batting team': 'SAUS', 'matchid2': '18770', 'matchno2': '21st Match', 'wickets10': '3', 'overs10': '49.4', 'matchtype2': 'TEST', 'runs1': '26', 'overs6': '8', 'runs6': '39', 'runs2': '49', 'name1': 'Mennie*', 'name5': 'Daniel Fallins*', 'series2': 'Sheffield Shield, 2017-18', 'Commentary1': '/Commentary5', 'wickets6': '1', 'runs11': '281', 'six1': '0', 'runs10': '192', 'balls1': '58', 'overs11': '74.1', 'maidens5': '1', 'desc21': '1st Inns', 'status2': 'South Aus won by 7 wkts', 'runs5': '51', 'wickets11': '10', 'desc11': '1st Inns', 'desc20': '2nd Inns', 'wickets20': '10', 'wickets21': '10', 'teams2': 'NSW vs SAUS', 'balls2': '85', 'Scorecard1': '/Scorecard5', 'wickets5': '1', 'progress2': 'Result', 'runs21': '256', 'fours2': '6', 'desc10': '2nd Inns', 'name6': 'Stobo', 'maidens6': '1', 'Bowling team': 'NSW', 'name2': 'Ferguson', 'overs20': '68.4', 'overs21': '90.4'}, {'six2': '0', 'scorecardid': 6, 'overs5': '4', 'fours1': '0', 'overs10': '20', 'Batting_team_img': 'images/RSA.png', 'wickets20': '5', 'wickets6': '1', 'Bowling_team_img': 'images/IND.png', 'maidens6': '0', 'Batting team': 'RSA', 'matchid2': '19166', 'name6': 'Unadkat', 'teams2': 'RSA vs IND', 'wickets10': '9', 'desc10': 'Inns', 'runs5': '32', 'matchtype2': 'T20', 'Scorecard1': '/Scorecard6', 'runs1': '2', 'wickets5': '0', 'runs6': '33', 'runs2': '0', 'maidens5': '0', 'runs20': '203', 'name5': 'Bumrah*', 'progress2': 'Result', 'Commentary1': '/Commentary6', 'fours2': '0', 'series2': 'India tour of South Africa, 2017-18', 'name1': 'Junior Dala*', 'commentaryid': 6, 'matchno2': '1st T20I', 'six1': '0', 'overs6': '4', 'Bowling team': 'IND', 'balls2': '2', 'balls1': '3', 'name2': 'Shamsi', 'overs20': '20', 'runs10': '175', 'desc20': 'Inns', 'status2': 'Ind won by 28 runs'}]
like image 411
steve Avatar asked Feb 19 '18 02:02

steve


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1 Answers

Since your records do not appear to have a unique identifier to differentiate records, you will need to hash on all key-value pairs. This approach will work as long as you do not have nested mutable objects inside your dictionaries.

I'll use an OrderedDict here to maintain order.

from collections import OrderedDict
list(
     map(
         dict, 
         OrderedDict.fromkeys(
             map(frozenset, map(dict.items, table)), None
         )
     )
)

[{'age': '2', 'h': '5', 'man': 'tim', 'w': '40'},
 {'age': '4', 'h': '3', 'man': 'jim', 'w': '20'},
 {'age': '24', 'h': '5', 'man': 'jon', 'w': '80'},
 {'age': '7', 'h': '4', 'man': 'tto', 'w': '49'}]

Here's what's going on:

  1. Convert each dictionary to a frozenset of tuples. frozensets are hashable.
  2. Hash each frozenset as a key into an OrderedDict. Duplicates are removed automatically.
  3. Retrieve keys and convert back into a list of dictionaries.

There are many ways to reproduce the algorithm described above. I've used the functional programming tool - map - which python offers.

like image 96
cs95 Avatar answered Oct 17 '22 09:10

cs95