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Say I have the following code:
struct test* t1;
t1 = get_t(1);
... where get_t is:
struct test* get_t(int);
How can I refactor the above code and put it in a function? Something like the following:
void r1(?* t, ?* (fn*)(int)) {
t = fn(1);
}
/* ... */
struct test* t1;
r1(t1, &get_t);
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If a function takes no parameters, the parameters may be left empty. The compiler will not perform any type checking on function calls in this case. A better approach is to include the keyword "void" within the parentheses, to explicitly state that the function takes no parameters.
Arguments are Passed by Value The parameters, in a function call, are the function's arguments. JavaScript arguments are passed by value: The function only gets to know the values, not the argument's locations. If a function changes an argument's value, it does not change the parameter's original value.
You can use a default argument in Python if you wish to call your function without passing parameters. The function parameter takes the default value if the parameter is not supplied during the function call.
use void *param, a pointer to anything ... commonly used in glib as gpointer
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