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How can I convert InputStream data to String in Android SOAP Webservices

When I am consuming the soap web services from Android I want to display the result in output string how can I convert that Input Stream to Sting?

  package com.venkattt.pack;

import java.io.BufferedReader;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.net.SocketException;

import org.ksoap2.SoapEnvelope;
import org.ksoap2.serialization.SoapObject;
import org.ksoap2.serialization.SoapPrimitive;
import org.ksoap2.serialization.SoapSerializationEnvelope;
import org.ksoap2.transport.AndroidHttpTransport;
import org.ksoap2.transport.HttpTransportSE;
import org.xmlpull.v1.XmlPullParser;
import org.xmlpull.v1.XmlPullParserFactory;

import android.app.Activity;
import android.os.Bundle;

public class SoapWebservicesExampleActivity extends Activity {
    /** Called when the activity is first created. */
      final String NAMESPACE = "urn:sap-com:document:sap:soap:functions:mc-style";
     final String URL = "http://**********:8000/sap/bc/srt/wsdl/srvc_14DAE9C8D79F1EE196F1FC6C6518A345/wsdl11/allinone/ws_policy/document?sap-client=800&sap-user=************&sap-password=*********";
      final String METHOD_NAME = "Z_GET_CUST_GEN";
     final String SOAP_ACTION = "urn:sap-com:document:sap:soap:functions:mc-style/Z_GET_CUST_GEN";
    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.main);
           SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME); // set up
            request.addProperty("Input", "1460");
            request.addProperty("Langu", "d");
            SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER12); // put all required data into a soap
            envelope.dotNet = true;
            envelope.setOutputSoapObject(request);
            HttpTransportSE httpTransport = new HttpTransportSE(URL);
            httpTransport.debug = true;

            try {


                 httpTransport.call(SOAP_ACTION, envelope);
                 SoapObject response = (SoapObject)envelope.getResponse();
                 String str = response.getProperty(0).toString();

                 System.out.println("theeeeeeeeeee"+str);



                }
            catch(SocketException ex){
                    ex.printStackTrace();

                } catch (Exception e) {
                   e.printStackTrace();
                }
        }


    }

my final code please look at once and let me know

where can I put that conversion in the above code?

like image 278
user1414667 Avatar asked May 25 '12 10:05

user1414667


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How do I change InputStream to string?

To convert an InputStream Object int to a String using this method. Instantiate the Scanner class by passing your InputStream object as parameter. Read each line from this Scanner using the nextLine() method and append it to a StringBuffer object. Finally convert the StringBuffer to String using the toString() method.

Which method is used to read a string from the input stream?

InputStream. read() method reads the next byte of the data from the the input stream and returns int in the range of 0 to 255.


2 Answers

   String  response = convertStreamToString(instream);

Method

private String convertStreamToString(InputStream is) {
    BufferedReader reader = new BufferedReader(new InputStreamReader(is));
    StringBuilder sb = new StringBuilder();

    String line = null;
    try {
        while ((line = reader.readLine()) != null) {
            sb.append(line).append('\n');
        }
    } catch (IOException e) {
        e.printStackTrace();
    } finally {
        try {
            is.close();
        } catch (IOException e) {
            e.printStackTrace();
        }
    }
    return sb.toString();
}
like image 151
Samir Mangroliya Avatar answered Oct 23 '22 19:10

Samir Mangroliya


import com.google.android.gms.common.util.IOUtils;

InputStream input = getInputStream();
String body = new String(IOUtils.toByteArray(input), "UTF-8");
input.close();
like image 40
Valdemar_Rudolfovich Avatar answered Oct 23 '22 20:10

Valdemar_Rudolfovich