How can I compare two files in a batch file?

Question

How can I compare two files in a batch file, and perform an action based on whether or not they match? I've tried something like:

if file1.txt NEQ file2.txt goto label

but it compares the actual string "file1.txt" rather than the file. I've read about the COMP command, but it doesn't seem to work if I put it in an if statement. Does anybody know how to do this? Sorry, but I rarely use batch files and have little experience in them.

Thanks in advance.

Answer 1

I believe you can use the "FC" command and then check the errorlevel. Here's some code:

@echo off
:main
fc c:\filename r:\filemame > nul
if errorlevel 1 goto error

:next
echo insert next CD
pause
goto main

:error
echo failed check

(Pulled from http://www.computing.net/answers/dos/batch-file-command/15753.html)

Answer 2

It seems like the COMP program is actually fairly easy to use. See this question on Yahoo answers.

Note that running comp /? will print the help text for the program (as does specifying the /? argument with any native Windows command line program). This outputs the same text you see in the answer of the question linked above.

Content from the Yahoo Answer:

C:\>comp /? 
Compares the contents of two files or sets of files. 

COMP [data1] [data2] [/D] [/A] [/L] [/N=number] [/C] [/OFF[LINE]] 

data1 Specifies location and name(s) of first file(s) to compare. 
data2 Specifies location and name(s) of second files to compare. 
/D Displays differences in decimal format. 
/A Displays differences in ASCII characters. 
/L Displays line numbers for differences. 
/N=number Compares only the first specified number of lines in each file. 
/C Disregards case of ASCII letters when comparing files. 
/OFF[LINE] Do not skip files with offline attribute set. 

To compare sets of files, use wildcards in data1 and data2 parameters.