I need to check if a value is an integer. I found this: How to check whether input value is integer or float?, but if I'm not mistaken, the variable there is still of type double
even though the value itself is indeed an integer
.
To check if the variable is an integer in Python, we will use isinstance() which will return a boolean value whether a variable is of type integer or not. After writing the above code (python check if the variable is an integer), Ones you will print ” isinstance() “ then the output will appear as a “ True ”.
We can use the isdigit() function to check if the string is an integer or not in Python. The isdigit() method returns True if all characters in a string are digits. Otherwise, it returns False.
If input value can be in numeric form other than integer , check by
if (x == (int)x) { // Number is integer }
If string value is being passed , use Integer.parseInt(string_var).
Please ensure error handling using try catch in case conversion fails.
If you have a double/float/floating point number and want to see if it's an integer.
public boolean isDoubleInt(double d) { //select a "tolerance range" for being an integer double TOLERANCE = 1E-5; //do not use (int)d, due to weird floating point conversions! return Math.abs(Math.floor(d) - d) < TOLERANCE; }
If you have a string and want to see if it's an integer. Preferably, don't throw out the Integer.valueOf()
result:
public boolean isStringInt(String s) { try { Integer.parseInt(s); return true; } catch (NumberFormatException ex) { return false; } }
If you want to see if something is an Integer object (and hence wraps an int
):
public boolean isObjectInteger(Object o) { return o instanceof Integer; }
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