Is there a way of checking if a string exists in an array of strings - without iterating through the array?
For example, given the script below, how I can correctly implement it to test if the value stored in variable $test exists in $array?
array=('hello' 'world' 'my' 'name' 'is' 'perseus')
#pseudo code
$test='henry'
if [$array[$test]]
then
do something
else
something else
fi
Note
I am using bash 4.1.5
You can use the includes() method in JavaScript to check if an item exists in an array. You can also use it to check if a substring exists within a string. It returns true if the item is found in the array/string and false if the item doesn't exist.
You can simply use . includes() method of arrays: let a = [2, 4, 6, 8, 10], b = 2; if(a. includes(b)) { // your code goes here... }
You cannot iterate over an array in c without knowking the number of elements. Please note that sizeof(array) / sizeof(array[0]) won't work on a pointer, i.e it will not give the number of elements in the array.
With bash 4, the closest thing you can do is use associative arrays.
declare -A map
for name in hello world my name is perseus; do
map["$name"]=1
done
...which does the exact same thing as:
declare -A map=( [hello]=1 [my]=1 [name]=1 [is]=1 [perseus]=1 )
...followed by:
tgt=henry
if [[ ${map["$tgt"]} ]] ; then
: found
fi
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