How would I validate that a program exists, in a way that will either return an error and exit, or continue with the script?
It seems like it should be easy, but it's been stumping me.
You can use the posix compatible command to check, if the command exists from a bash script or not. if it returns >0 when the command is not found or an error occurs. similary you can use type and hash .
To check if the a file is readable, in other words if the file has read permissions, using bash scripting, use [ -r FILE ] expression with bash if statement.
To check if a variable is set in Bash Scripting, use-v var or-z ${var} as an expression with if command. This checking of whether a variable is already set or not, is helpful when you have multiple script files, and the functionality of a script file depends on the variables set in the previously run scripts, etc.
POSIX compatible:
command -v <the_command>
Example use:
if ! command -v <the_command> &> /dev/null then echo "<the_command> could not be found" exit fi
For Bash specific environments:
hash <the_command> # For regular commands. Or... type <the_command> # To check built-ins and keywords
Avoid which
. Not only is it an external process you're launching for doing very little (meaning builtins like hash
, type
or command
are way cheaper), you can also rely on the builtins to actually do what you want, while the effects of external commands can easily vary from system to system.
Why care?
which
that doesn't even set an exit status, meaning the if which foo
won't even work there and will always report that foo
exists, even if it doesn't (note that some POSIX shells appear to do this for hash
too).which
do custom and evil stuff like change the output or even hook into the package manager.So, don't use which
. Instead use one of these:
$ command -v foo >/dev/null 2>&1 || { echo >&2 "I require foo but it's not installed. Aborting."; exit 1; } $ type foo >/dev/null 2>&1 || { echo >&2 "I require foo but it's not installed. Aborting."; exit 1; } $ hash foo 2>/dev/null || { echo >&2 "I require foo but it's not installed. Aborting."; exit 1; }
(Minor side-note: some will suggest 2>&-
is the same 2>/dev/null
but shorter – this is untrue. 2>&-
closes FD 2 which causes an error in the program when it tries to write to stderr, which is very different from successfully writing to it and discarding the output (and dangerous!))
If your hash bang is /bin/sh
then you should care about what POSIX says. type
and hash
's exit codes aren't terribly well defined by POSIX, and hash
is seen to exit successfully when the command doesn't exist (haven't seen this with type
yet). command
's exit status is well defined by POSIX, so that one is probably the safest to use.
If your script uses bash
though, POSIX rules don't really matter anymore and both type
and hash
become perfectly safe to use. type
now has a -P
to search just the PATH
and hash
has the side-effect that the command's location will be hashed (for faster lookup next time you use it), which is usually a good thing since you probably check for its existence in order to actually use it.
As a simple example, here's a function that runs gdate
if it exists, otherwise date
:
gnudate() { if hash gdate 2>/dev/null; then gdate "$@" else date "$@" fi }
You can use scripts-common to reach your need.
To check if something is installed, you can do:
checkBin <the_command> || errorMessage "This tool requires <the_command>. Install it please, and then run this tool again."
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