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I have a list called pairs.
pairs = [("a", 1), ("b", 2), ("c", 3)] And I can access elements as:
for x in pairs: print x which gives output like:
('a', 1) ('b', 2) ('c', 3) But I want to access each element in each pair, like in c++, if we use pair<string, int> we are able to access, first element and second element by x.first, and x.second.eg.
x = make_pair("a",1) x.first= 'a' x.second= 1 How can I do the same in python?
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So you can access the first element of that thing by specifying [0] or [1] after its name. So all you have to do to get the first element of the first element of pair is say pair[0][0] . Or if you want the second element of the third element, it's pair[2][1] .
Compare the n-th items of both tuple (starting with the zero-th index) using the == operator. If both are equal, repeat this step with the next item. For two unequal items, the item that is “less than” makes the tuple, that contains it, also “less than” the other tuple. If all items are equal, both tuples are equal.
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Is there simpler way of printing sequence of number pairs (two numbers) in python3 ? for x in range(0,n): # [0, n-1] print("{} {}". format(x, x*x));
Use tuple unpacking:
>>> pairs = [("a", 1), ("b", 2), ("c", 3)] >>> for a, b in pairs: ... print a, b ... a 1 b 2 c 3 See also: Tuple unpacking in for loops.
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