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What happens internally when a functions that uses varargs is called? Are the arguments themselves stored on the heap or on the stack like any other arguments. If on the stack, how does that work?
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To provide variable-length parameters, we need to use an asterisk before the parameter name in the given method. The type of parameters supplied is a tuple, and within the method, these passed arguments form a tuple with the same name as the parameter, excluding the asterisk.
Variable length argument is a feature that allows a function to receive any number of arguments. There are situations where we want a function to handle variable number of arguments according to requirement.
Syntax of VarargsA variable-length argument is specified by three periods or dots(…). This syntax tells the compiler that fun( ) can be called with zero or more arguments. As a result, here, a is implicitly declared as an array of type int[].
It's implementation-dependent. But most probably, the args are placed on the stack, one after the other (after default argument promotions have been performed).
va_start, va_arg etc. work by simply walking a pointer through the stack, and reinterpreting the bits as whatever type you ask for.
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