Logo Questions Linux Laravel Mysql Ubuntu Git Menu
 

Hot and Cold observables: are there 'hot' and 'cold' operators?

I reviewed the following SO question: What are the Hot and Cold observables?

To summarize:

  • a cold observable emits its values when it has an observer to consume them, i.e. the sequence of values received by observers is independent of time of subscription. All observers will consume the same sequence of values.
  • a hot observable emits value independently of its subscriptions, i.e. the values received by observers are a function of the time of subscription.

Yet, I feel like hot vs. cold is still a source of confusion. So here are my questions:

  • Are all rx observables cold by default (with the exception of subjects)?

    I often read that events are the typical metaphor for hot observables, but I also read that Rx.fromEvent(input, 'click') is a cold observable(?).

  • Are there/what are the Rx operators which turn a cold observables into a hot observable (apart from publish, and share)?

    For instance, how does it work with Rx operator withLatestFrom? Let cold$ be a cold observable which has somewhere been subscribed to. Will sth$.withLatestFrom(cold$,...) be a hot observable?

    Or if I do sth1$.withLatestFrom(cold$,...), sth2$.withLatestFrom(cold$,...) and subscribe to sth1 and sth2, will I always see the same value for both sth?

  • I thought Rx.fromEvent creates cold observables but that is not the case, as mentioned in one of the answers. However, I am still baffled by this behaviour: https://codepen.io/anon/pen/NqQMJR?editors=101. Different subscriptions get different values from the same observable. Wasn't the click event shared?

like image 784
user3743222 Avatar asked Aug 24 '15 19:08

user3743222


People also ask

Are observables hot or cold?

An Observable is cold when data is produced inside the Observable and the Observable is hot when the data is produced outside the Observable.

Is fromEvent hot or cold?

fromEvent(input, 'click') is a cold observable(?).

Which operator is used to create an observable?

Creation Operators This operator will create an observable from an array, an array-like object, a promise, an iterable object, or an observable-like object. This operator will give output as an observable that is to be used on elements that emit an event for example buttons, clicks, etc.

Which method is used in RxJS to work on multiple operators together in sequential order?

ConcatAll This operator combines all emitted inner streams and just as with plain concat sequentially produces values from each stream.

What is the difference between cold and hot observables?

There are two types of observables: hot and cold. The main difference is that a cold observable creates a data producer for each subscriber, whereas a hot observable creates a data producer first, and each subscriber gets the data from one producer, starting from the moment of subscription.

What makes a hot observable cold in JavaScript?

It makes a hot observable or observable-returning function cold. Operators such as Merge and Concat, among many other combining/zipping/joining operators, can add subscription side effects to hot observables by combining them with cold observables, thus returning cold observables.

What are the different types of observables?

Observables can be classified into two main groups: hot and cold Observables. Let's start with a cold Observable. Copied! In the above case subscriber B subscribes 2000ms after subscriber A.

What is the temperature of an observable?

In the simplest case, an observable may be permanently hot or permanently cold , though some observables change their temperature over time so that different observers may get different temperatures; therefore: The temperature of an observable is relative to the time of subscription.


2 Answers

I am coming back a few months later to my original question and wanted to share the gained knowledge in the meanwhile. I will use the following code as an explanation support (jsfiddle):

var ta_count = document.getElementById('ta_count'); var ta_result = document.getElementById('ta_result'); var threshold = 3;  function emits ( who, who_ ) {return function ( x ) {   who.innerHTML = [who.innerHTML, who_ + " emits " + JSON.stringify(x)].join("\n"); };}  var messages$ = Rx.Observable.create(function (observer){   var count= 0;   setInterval(function(){     observer.onNext(++count);   }, 1000) }) .do(emits(ta_count, 'count')) .map(function(count){return count < threshold}) .do(emits(ta_result, 'result'))  messages$.subscribe(function(){}); 

As mentioned in one of the answers, defining an observable leads to a series of callback and parameter registration. The data flow has to be kicked in, and that is done via the subscribe function. A (simplified for illustration) detailed flow can be find thereafter.

Simplified flow diagram

Observables are cold by default. Subscribing to an observable will result in an upstream chain of subscriptions taking place. The last subscription leads to the execution of a function which will handle a source and emit its data to its observer.

That observer in its turn emits to the next observer, resulting in a downstream flow of data, down to the sink observer. The following simplified illustration shows subscription and data flows when two subscribers subscribe to the same observable.

Cold observable simplified flow diagram

Hot observables can be created either by using a subject, or through the multicast operator (and its derivatives, see Note 3 below).

The multicast operator under the hood makes use of a subject and returns a connectable observable. All subscriptions to the operator will be subscriptions to the inner subject. When connect is called, the inner subject subscribes to the upstream observable, and data flows downstream. Subjects manipulate internally a list of subscribed observers and multicast incoming data to all subscribed observers.

The following diagram summarizes the situation.

Hot observable simplified flow diagram

In the end, it matters more to understand the flow of data caused by the observer pattern and the implementation of the operators.

For instance, if obs is hot, is hotOrCold = obs.op1 cold or hot? Whatever the answer is :

  • if there are no subscribers to obs.op1, no data will flow through op1. If there were subscribers to hot obs, that means obs.op1 will have possibly lost pieces of data
  • supposing that op1 is not a multicast-like operator, subscribing twice to hotOrCold will subscribe twice to op1, and every value from obs will flow twice through op1.

Notes :

  1. This information should be valid for Rxjs v4. While the version 5 has gone through considerable changes, most of it still applies verbatim.
  2. Unsubscription, error and completion flows are not represented, as they are not in the scope of the question. Schedulers are also not taken into account. Among other things, they influence the timing of the data flow, but a priori not its direction and content.
  3. According to the type of subject used for multicasting, there are different derived multicasting operators:

Subject type | `Publish` Operator | `Share` operator ------------------ | --------------------------- | ----------------- Rx.Subject | Rx.Observable.publish | share Rx.BehaviorSubject | Rx.Observable.publishValue | shareValue Rx.AsyncSubject | Rx.Observable.publishLast | N/A Rx.ReplaySubject | Rx.Observable.replay | shareReplay

Update : See also the following articles, here, and there) on that subject by Ben Lesh.

Further details on subjects can be found in this other SO question : What are the semantics of different RxJS subjects?

like image 144
user3743222 Avatar answered Sep 26 '22 01:09

user3743222


Your summary, and the linked question are both correct, I think the terminology may be confusing you. I propose you think of hot and cold observables as active and passive observables (respectively).

That is, an active (hot) observable will be emitting items whether someone has subscribed or not. The canonical example, again, button click events happen whether someone is listening to them or not. This distinction is important because, if, for example, I click a button and then subscribe to button clicks (in that order), I will not see the button click that has already happened.

A passive (cold) observable will wait until a subscriber exists before emitting items. Imagine a button where you cannot click on it until someone is listening to the events—this would ensure that you always see each and every click event.

Are all Rx observables "cold" (or passive) by default? No, Rx.fromEvent(input, 'click') for example is a hot (or active) observable.

I also read that Rx.fromEvent(input, 'click') is a cold observable(?)

That is not the case.

Are there Rx operators which turn a cold observable into a hot observable?

The concept of turning a hot (active) observable into a cold (passive) observable is this: you need to record the events that happen while nothing is subscribed and offer those items (in various ways) to subscribers that come along in the future. One way to do this is to use a Subject. For example, you could use a ReplaySubject to buffer up items emitted and replay them to future subscribers.

The two operators you named (publish and share) both use subjects internally to offer that functionality.

How does it work with Rx operator withLatestFrom? Let cold$ be a cold observable which has been subscribed to. Will something$.withLatestFrom(cold$,...) be a hot observable?

If something is a hot observable, then yes. If something is a cold observable, then no. Going back to the events example, if something is a stream of button click events:

var clickWith3 = Rx.fromEvent(input, 'click')     .withLatest(Rx.Observable.from([1, 2, 3]); 

Or if I do foo$.withLatestFrom(cold$,...), bar$.withLatestFrom(cold$,...) and subscribe to foo and bar, will I always see the same values for both?

Not always. Again, if foo and bar are clicks on different buttons for example, then you would see different values. As well, even if they were the same button, if your combination function (the 2nd argument to withLatest) does not return the same result for the same inputs, then you would not see the same values (because it would be called twice, as explained below).

I thought Rx.fromEvent creates cold observables but that is not the case, as mentioned in one of the answers. However, I am still baffled by this behaviour: codepen.io/anon/pen/NqQMJR?editors=101. Different subscriptions get different values from the same observable. Wasn't the click event shared?

I'll point you to this great answer by Enigmativity to a question I had about the same behaviour. That answer will explain it a lot better than I can, but the gist of it is that the source (the click event) is "shared", yes, but your operations on it are not. If you want to share not just the click event but also the operation on it, you will need to do so explicitly.

like image 35
Whymarrh Avatar answered Sep 22 '22 01:09

Whymarrh