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hog() got an unexpected keyword argument 'visualize'

I am running the scikit-image Histogram of Gradients example

The example code is as follows:

import matplotlib.pyplot as plt

from skimage.feature import hog
from skimage import data, color, exposure


image = color.rgb2gray(data.astronaut())

fd, hog_image = hog(image, orientations=8, pixels_per_cell=(16, 16),
                    cells_per_block=(1, 1), visualize=True)

fig, (ax1, ax2) = plt.subplots(1, 2, figsize=(8, 4), sharex=True, sharey=True)

ax1.axis('off')
ax1.imshow(image, cmap=plt.cm.gray)
ax1.set_title('Input image')
ax1.set_adjustable('box-forced')

# Rescale histogram for better display
hog_image_rescaled = exposure.rescale_intensity(hog_image, in_range=(0, 0.02))

ax2.axis('off')
ax2.imshow(hog_image_rescaled, cmap=plt.cm.gray)
ax2.set_title('Histogram of Oriented Gradients')
ax1.set_adjustable('box-forced')
plt.show()

Put simply, it does not work and reports the following error:

    fd, hog_image = hog(image, orientations=8, pixels_per_cell=(16, 16), cells_per_block=(1, 1), visualize=True)
TypeError: hog() got an unexpected keyword argument 'visualize'

I can view the astronaut image by commenting out the above section, so that is not the problem. Does anyone know why it is failing?

like image 653
SeanJ Avatar asked Oct 01 '17 20:10

SeanJ


1 Answers

It is a very small error but the spelling for your keyword argument visualize is wrong. It should be

fd, hog_image = hog(image, orientations=8, pixels_per_cell=(16, 16),
                cells_per_block=(1, 1), visualise=True)

Refer here for more information.

like image 169
Lakshya Kejriwal Avatar answered Oct 24 '22 07:10

Lakshya Kejriwal