I have this exception :
org.hibernate.MappingException: persistent class not known: java.lang.Long
I'm using Hibernate 5.1.0.Final and spring-orm 4.2.4.RELEASE
My spring configuration file (spring.xml
) :
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:aop="http://www.springframework.org/schema/aop"
xmlns:tx="http://www.springframework.org/schema/tx"
xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/aop http://www.springframework.org/schema/aop/spring-aop-4.0.xsd
http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx-4.0.xsd">
<bean id="dataSource" class="org.apache.commons.dbcp.BasicDataSource"
destroy-method="close">
<property name="driverClassName" value="com.mysql.jdbc.Driver" />
<property name="url" value="jdbc:mysql://localhost/ecollection" />
<property name="username" value="root" />
<property name="password" value="" />
</bean>
<bean id="hibernateAnnotatedSessionFactory"
class="org.springframework.orm.hibernate5.LocalSessionFactoryBean">
<property name="dataSource" ref="dataSource" />
<property name="annotatedClasses">
<list>
<value>com.ecollection.model.Adresse</value>
<value>com.ecollection.model.Utilisateur</value>
</list>
</property>
<property name="hibernateProperties">
<props>
<prop key="hibernate.dialect">org.hibernate.dialect.MySQL5InnoDBDialect</prop>
<prop key="hibernate.current_session_context_class">thread</prop>
<prop key="hibernate.show_sql">false</prop>
</props>
</property>
</bean>
<bean id="utilisateurDao" class="com.ecollection.dao.UtilisateurDaoImpl">
<property name="sessionFactory" ref="hibernateAnnotatedSessionFactory" />
</bean>
<bean id="adresseDao" class="com.ecollection.dao.AdresseDaoImpl">
<property name="sessionFactory" ref="hibernateAnnotatedSessionFactory" />
</bean>
And I have two MySQL tables, User
and Address
.
User = Id, Name and Firstname
Address = Id, Street, City and UserId
for UserId in my Address entitybean, I'm doing this :
@OneToOne
@JoinColumn(name="id")
public Long getIdUtilisateur() {
return idUtilisateur;
}
Missing or Invalid @Entity Annotation The most common cause for the mapping exception is simply an entity class missing the @Entity annotation: Another possibility is that it may have the wrong type of @Entity annotation: import org.hibernate.annotations.Entity; @Entity public class Foo implements Serializable { ...
MappingException With Spring The configuration of Hibernate in Spring involves bootstrapping the SessionFactory from annotation scanning, via a LocalSessionFactoryBean: This simple configuration of the Session Factory Bean is missing a key ingredient, and a test trying to use the SessionFactory will fail:
An exception that occurs while reading mapping sources (xml/annotations),usually as a result of something screwy in the O-R mappings. Constructs a MappingException using the given information. Fake signature of an existing Java class. Walk the nodes of the tree left-to-right or right-to-left.
The configuration of Hibernate in Spring involves bootstrapping the SessionFactory from annotation scanning, via a LocalSessionFactoryBean: This simple configuration of the Session Factory Bean is missing a key ingredient, and a test trying to use the SessionFactory will fail: ...
You can not use a non entity as a target for OneToOne
or JoinColumn
, as you did here:
@OneToOne
@JoinColumn(name="id")
public Long getIdUtilisateur() {
return idUtilisateur;
}
Instead you can use this approach for mapping Utilisateur
and Address
relationship:
@OneToOne
@JoinColumn(name="id")
public Utilisateur getUtilisateur() {
return utilisateur;
}
Of course, Utilisateur
should be an entity:
@Entity
public class Utilisateur { ... }
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