I have a beginner question about dates and String
in Haskell.
I need to get part of date (year, month or day) as String
in Haskell. I found out, that if I write the following two lines in GHCi
Prelude> now <- getCurrentTime
Prelude> let mon = formatTime defaultTimeLocale "%B" now
then mon
is of type String
. However, I am unable to put this in a function. I tried for instance the following:
getCurrMonth = do
now <- getCurrentTime
putStrLn (formatTime defaultTimeLocale "%B" now)
But this returns type IO ()
and I need String
(also not IO String
, only String
).
I understand that do
statement creates a monad, which I don't want, but I have been unable to find any other solution for getting date in Haskell.
So, is there any way to write a function like this?
Thanks in advance for any help!
If you want to return a String representing the current time, it will have to be in the IO monad, as the value of the current time is always changing!
What you can do is to return a String in the IO monad:
> getCurrMonth :: IO String
> getCurrMonth = do
> now <- getCurrentTime
> return (formatTime defaultTimeLocale "%B" now)
then, from your top level (e.g. in main), you can pass the String around:
> main = do
> s <- getCurrMonth
> ... do something with s ...
If you really want a pure function of that sort, then you need to pass in the time explicitly as a parameter.
import System.Locale (defaultTimeLocale)
import System.Time (formatCalendarTime, toUTCTime, getClockTime, ClockTime)
main = do now <- getClockTime
putStrLn $ getMonthString now
getMonthString :: ClockTime -> String
getMonthString = formatCalendarTime defaultTimeLocale "%B" . toUTCTime
Notice how getMonthString
can be pure since the IO action getClockTime
is performed elsewhere.
I used the old-time functions, because I was testing it out on codepad, which apparently doesn't have the newer time package. :( I'm new to the old time functions so this might be off a couple hours since it uses toUTCTime
.
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