I am curious to know what is the reasoning that could overweighs towards using a self-balancing tree technique to store items than using a hash table.
I see that hash tables cannot maintain the insertion-order, but I could always use a linked list on top to store the insertion-order sequence.
I see that for small number of values, there is an added cost of of the hash-function, but I could always save the hash-function together with the key for faster lookups.
I understand that hash tables are difficult to implement than the straight-forward implementation of a red-black tree, but in a practical implementation wouldn't one be willing to go an extra mile for the trouble?
I see that with hash tables it is normal for collisions to occur, but with open-addressing techniques like double hashing that allow to save the keys in the hash table itself, hasn't the problem been reduced to the effect of not tipping the favor towards red black trees for such implementations?
I am curious if I am strictly missing a disadvantage of hash table that still makes red black trees quite viable data structure in practical applications (like filesystems, etc.).
Binary Search Trees are generally memory-efficient since they do not reserve more memory than they need to. On the other hand, Hash tables can be a bit more demanding if we don't know the exact number of elements we want to store.
Hashing gives a more secure and adjustable method of retrieving data compared to any other data structure. It is quicker than searching for lists and arrays.
In BST we can do range searches efficiently but in Hash Table we cannot do range search efficienly. BST are memory efficient but Hash table is not.
What is the advantage of a hash table over BST? Explanation: Hash table and BST both are examples of data structures. Hash table has an advantage that it has a better time complexity for performing insert, delete and search operations.
Here is what I can think of:
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