Logo Questions Linux Laravel Mysql Ubuntu Git Menu
 

GWT: Dealing with incoming JSON string

Tags:

java

json

gwt

I am working on a GWT app that is receiving a JSON string, and I'm having a hard time getting down to the values of each object. I'm trying to transfer the incoming JSON string into an array of objects.

Here is the JSON (from Firebug response tab), The "d" is a .NET thing (Web Service Being Consumed is C#.

{
    "d": [
        {
            "__type": "Event",
            "ID": 30,
            "Bin": 1,
            "Date": "\/Date(1281544749000)\/",
            "Desc": "Blue with white stripes.",
            "Category": "1"
        },
        {
            "__type": "Event",
            "ID": 16,
            "Bin": 3,
            "Date": "\/Date(1281636239000)\/",
            "Desc": "Yellow with pink stripes",
            "Category": "1"
        }

    ]
}

I'm trying to parse the JSON into objects, and then insert them into an array. I'm able to use Window.alert and get the entire "d" object to echo. However, when I try to access the elements of the array, GWT debugger just crashes.

//My GWT array to receive JSON Array
ArrayList<Item> itemInfo = new ArrayList<Item>();

//Getting response JSON into something I can work with.(THIS FAILS) 
JSONArray jsonValue = JSONParser.parse(incomingJsonRespone);

//Just trying to verify I'm getting values 
for (int i=0; i<jsonValue.size(); i++) {
    JSONValue jsonItem =  = JsonValue.get(i).getString();
    Window.alert(jsonItem);
    itemInfo.add(jsonItem);

}

I think I have narrowed down the problem to where the JSONArray instance is being created. Is there something blatantly wrong with how I'm trying to do this, because I'm not getting much help in the way of error messages?

like image 492
tpow Avatar asked Aug 16 '10 02:08

tpow


2 Answers

In response to RMorrisey's comment:
Actually, it's more convoluted :/ It would look something like this (code untested, but you should get the general idea):

JSONValue jsonValue;
JSONArray jsonArray;
JSONObject jsonObject;
JSONString jsonString;
jsonValue = JSONParser.parseStrict(incomingJsonRespone);
// parseStrict is available in GWT >=2.1
// But without it, GWT is just internally calling eval()
// which is strongly discouraged for untrusted sources

if ((jsonObject = jsonValue.isObject()) == null) {
    Window.alert("Error parsing the JSON");
    // Possibilites: error during download,
    // someone trying to break the application, etc.
}

jsonValue = jsonObject.get("d"); // Actually, this needs
                                 // a null check too
if ((jsonArray = jsonValue.isArray()) == null) {
    Window.alert("Error parsing the JSON");
}

jsonValue = jsonArray.get(0);
if ((jsonObject = jsonValue.isObject()) == null) {
    Window.alert("Error parsing the JSON");
}

jsonValue = jsonObject.get("Desc");
if ((jsonString = jsonValue.isString()) == null) {
    Window.alert("Error parsing the JSON");
}

Window.alert(jsonString.stringValue()); // Finally!

As you can see, when using JSONParser you have to/should be very cautious - that's the whole point, right? To parse an unsafe JSON (otherwise, like I suggested in the comments, you should go with JavaScript Overlay Types). You get a JSONValue, check if it's really what you think it should be, say, a JSONObject, you get that JSONObject, check if it has the "xyz" key, you get a JSONValue, rinse and repeat. Not the most interesting work, but at least its safer than just calling eval() on the whole JSON :)
Attention: as Jason pointed out, prior to GWT 2.1, JSONParser used eval() internally (it only had a parse() method - GWT 2.0 javadocs vs GWT 2.1). In GWT 2.1, parse() became deprecated and two more methods were introduced - parseLenient() (uses eval() internally) and parseStrict() (the safe approach). If you really have to use JSONParser, then I'd suggest upgrading to GWT 2.1 M2, because otherwise you might as well use JSOs. As an alternative to JSONParser for untrusted sources, you could try integrating json2.js as a JSON parser via JSNI.

PS: cinqoTimo, JSONArray jsonValue = JSONParser.parse(incomingJsonRespone); obviously doesn't work because JSONParser.parse has a return type of JSONValue, not JSONArray - didn't your IDE (Eclipse + Google Plugin?) warn you? Or at least the compiler.

like image 87
Igor Klimer Avatar answered Oct 23 '22 12:10

Igor Klimer


It looks like you don't have an array, but a single root object, whose property called 'd' is an array. I'm not familiar with that specific API, but maybe you can try retrieving a JSONObject or similar instead of an array?

like image 23
RMorrisey Avatar answered Oct 23 '22 11:10

RMorrisey