Here is a composed task I don't know how to replace it with task dependencies.
... gulp.task('watch', function () { var server = function(){ gulp.run('jasmine'); gulp.run('embed'); }; var client = function(){ gulp.run('scripts'); gulp.run('styles'); gulp.run('copy'); gulp.run('lint'); }; gulp.watch('app/*.js', server); gulp.watch('spec/nodejs/*.js', server); gulp.watch('app/backend/*.js', server); gulp.watch('src/admin/*.js', client); gulp.watch('src/admin/*.css', client); gulp.watch('src/geojson-index.json', function(){ gulp.run('copygeojson'); }); });
The corresponding changelog https://github.com/gulpjs/gulp/blob/master/CHANGELOG.md#35 [deprecate gulp.run]
If you just want a task that runs some function, then just do that: gulp. task('my-custom-task', function () { myCustomFunction('foo', 'bar'); });
Advertisements. The Watch method is used to monitor your source files. When any changes to the source file is made, the watch will run an appropriate task. You can use the 'default' task to watch for changes to HTML, CSS, and JavaScript files.
Or you can do like this:
gulp.start('task1', 'task2');
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